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IceJOKER [234]
3 years ago
5

A group of atoms that may act as an ion is referred to as _________???

Chemistry
1 answer:
rodikova [14]3 years ago
3 0
A group of atoms that may act as an ion is referred to as <span>radical </span>group. It is an<span> atom or </span>group<span> of atoms that has at least one unpaired electron and is therefore unstable and highly reactive. Hope this answers the question. Have a nice day.</span>
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7 0
3 years ago
A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou
qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

8 0
3 years ago
Scientist can use trees to look at climates of the past. How? What information can they gather and how do they gather it? Explai
andrezito [222]

Explanation:

Scientist use trees a whole lot to look at climate of the past by examining tree rings.

These are layers of cambium in each successive years formed. They have an annual growth pattern and are known as tree rings.

Tree rings can be used to decipher the age of a tree.

  • These three rings can be used to interpret climatic patterns.
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6 0
3 years ago
Which phase is heat energy being released?
scZoUnD [109]

The answer is B
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6 0
3 years ago
Electrochemical cells can be used to measure ionic concentrations. A cell is set up with a pair of Zn electrodes, each immersed
Phantasy [73]

Answer:

the concentration of the solution is 0.00906 M

Explanation:

Given the data in the question;

we know that from Nernst Equation;

E = E⁰ - ((0.0592/n) logQ)

now, E₀ for concentration cell is 0

n for this redox is 2

concentration of the unknown solution is x

so we substitute

0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))

0.045 = -0.0296log( x/0.300 )

divide both side by 0.0296

1.52 = -log( x/0.300 )

x/0.300 = 10^{-1.52

x/0.300 = 0.0301995

we cross multiply

x = 0.300 × 0.0301995

x =  0.00906 M

Therefore, the concentration of the solution is 0.00906 M

6 0
3 years ago
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