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3 years ago

The sum of 6 times a number and 3 is 2

Mathematics

1 answer:

Harrizon [31]3 years ago

5 0

Answer:

-1/6

Step-by-step explanation:

I put it into an equation. The periods are a result of autocorrect.

6x+3=2

-3. -3

________

6x= -1

--- ---

6. 6

X = -1/6

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How do trapezoid ABCD and A'B'C'D compare

Taya2010 [7]

Trapezoid ABCD was the original figure for trapezoid A'B'C'D. They are similar because they are the same shape, Trapezoid A'B'C'D is slightly bigger or smaller because it was dilated from trapezoid ABCD.

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3 years ago

X/a+x/b=1<br>make x the subject of the formular

monitta

Answer:

x = $\frac{ab}{b+a}$

Step-by-step explanation:

Given

$\frac{x}{a}$ + $\frac{x}{b}$ = 1

Multiply through by ab to clear the fractions

bx + ax = ab ← factor out x from each term on the left side

x(b + a) = ab ← divide both sides by (b + a)

x = $\frac{ab}{b+a}$

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3 years ago

Make sure to SHOW WORK

attashe74 [19]

9/4=2.25
2.25-1= 1.25

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3 years ago

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Umnica [9.8K]

Answer:

me too

Step-by-step explanation:

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3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago