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3 years ago

The variables _ and __ affect the gravitational force between objects.

Physics

2 answers:

german3 years ago

8 0

Mass................And........................Distance

SOVA2 [1]3 years ago

7 0

Answer:

mass and distance

Explanation:

Amazingly, gravity is Nature's weakest force among the four known forces. If the objects are very "light" (little mass), we do not even feel the attraction they make to each other, even though it exists. But when one (or both) has too much matter (mass), the force can already be perceived. This is the case of the weight of objects, which is the force that the earth makes on them. So weight is the result of gravity when one of the objects is the earth (or another celestial body if you are on it).

Based on this an experiment was made in the laboratory to study gravity. Two not very large objects were placed next to each other and the force of gravity was measured. This was only possible because the instruments were very sensitive. A mathematical formula was found that serves to calculate the value of the gravitational force between two objects when we know their masses and the distance between them. In this case, mass and distance are the two variables that affect the gravitational force between objects.

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Name two energy transformations that occur as Adeline pedals her bicycle up a steep hill and then coasts down the other side.

Juliette [100K]

Potential energy is first transformed into kinetic energy as she pedals, then gravitational as she coasts down the hill.

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4 years ago

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A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant

PIT_PIT [208]

Answer:

$9.96\cdot 10^{-10}J$

Explanation:

The capacitance of the parallel-plate capacitor is given by

$C=\epsilon_0 k \frac{A}{d}$

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

$A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2$ is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

$C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F$

Now we can calculate the energy of the capacitor, given by:

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

$U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J$

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3 years ago

Suppose you take a short piece of wire that is not attached to anything and move it up and down in a magnetic field. Explain whe

Otrada [13]

Answer:

No.

Explanation:

According to Faraday's law, the induced emf in the circuit is given by :

$e=\dfrac{d\phi}{dt}$ , it is proportional to the rate of change of magnetic flux.

In this case, a short piece of wire that is not attached to anything and move it up and down in a magnetic field. It means that the circuit is not completed here. It is an open circuit. For the induction of current, a circuit must be completed.
Hence, no current will induce.

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4 years ago

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By definition, acceleration is (5 Points)

Dovator [93]

Acceleration is a change in speed and/or direction

Explanation:

The acceleration of an object is defined as the rate of change of velocity, mathematically:

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity

$\Delta t$ is the time taken for the velocity of the object to change

We notice that velocity is a vector quantity, so it consists of:

- A magnitude, which is called speed

- A direction

Since acceleration is the rate of change in velocity, this means that the acceleration is non-zero whenever $\Delta v$ is non-zero, which means that either the speed AND/OR the direction of the velocity is changing.

For instance:

- For an object which is speeding up along a straight line, the speed is changing but the direction is not --> still, the object is accelerating

- For an object moving in a uniform circular motion, the speed is constant while the direction is changing --> still, the object is accelerating

So the correct answer is

a change in speed and/or direction

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