Use the coefficients as a ratio. 1:6 = x:24. You can write these as fractions and cross multiply, 6x=24. Solve and x=4, so four molecules would be needed
Answer: 40.68 kPa
Explanation:
Given that,
Original volume of gas V1 = 21.7 mL
Original pressure of gas P1 = 98.8 kPa
New volume of gas V2 = 52.7 mL
New pressure of gas P2 = ?
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
98.8 kPa x 21.7 mL = P2 x 52.7L
2143.96 kPa L = 52.7 L x P2
P2 = 2143.96 kPa L / 52.7 L
P2 = 40.68 kPa
Thus, the new pressure of the gas is 40.68 kPa.
a. pH=2.07
b. pH=3
c. pH=8
<h3>Further explanation</h3>
pH=-log [H⁺]
a) 0.1 M HF Ka = 7.2 x 10⁻⁴
HF= weak acid
b) 1 x 10⁻³ M HNO₃
HNO₃ = strong acid
c) 1 x 10⁻⁸ M HCl