London dispersion
dipole-dipole
Answer:
1.58×10E18
Explanation:
Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.
E°cell= 1.07- 0.53= 0.54 V
E°cell= 0.0592/n logK
0.54 = 0.0592/2 logK
logK= 0.54/0.0296
logK= 18.2
K= Antilog (18.2)
K= 1.58×10^18
Most reasonable answer:
Observations and experimentation
Answer:
YES BC ATMONS ARE THE SMALLEST UNIT sorry for caps
Explanation:
Sulfur is not a transition metal so it does not need a Roman numeral the correct answer is Trisulfur Dichloride