The volume of ammonia gas is 4096 mL.
Explanation:
As per the kinetic theory of gases, the volume occupied by gas molecules will be directly proportional to the temperature and number of moles of the gas molecules. Similarly, the volume occupied by gas molecules will be inversely proportional to pressure.
PV = nRT
So, V = nRT/P
As R = 0.082 L atm mol⁻¹ K⁻¹ , T = 273 K and P = 1 atm with n = 0.183 mol
Then,
V=(0.183*0.082*273)/1
V = 4.096 L = 4096 mL.
Thus, the volume of ammonia gas is 4096 mL.
The mass number of the atom is 21, the atomic number is 9, and the element is Fluorine. There are 9 protons, 9 electrons, 12 neutrons, and the elemental symbol is F.
<h3>Properties of an atom</h3>
For every atom:
- Protons and neutrons are located in the nucleus and the addition of both equals the mass number of atoms.
- Electrons are located outside the nucleus, in orbitals.
- Neutral atoms have the same number of electrons and protons
In the diagram:
Number of electrons = 9
Number of protons = 9
Number of neutrons = 12
Mass number = 12 + 9
= 21
Atomic number = number of protons
= 9
Element with atomic number 9 = Fluorine
Symbol of the element = F
More on atoms can be found here: brainly.com/question/1566330
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Answer:
<em>2NaOH+ H2SO4 → Na2SO4 + 2H2O</em>
<h3>I HOPE ITS RIGHT IF NOT THEN SORRY</h3>
HAVE A GREAT DAY :)
22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
To find the mass, the given data was,
Volume = 11.6 Liters
<h3>What is decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:
2 NaN₃ ⇒ 2 Na + 3 N₂
We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.
- At STP, 1 mole of N₂ occupies 22.4 L.
- The molar ratio of N₂ to NaN₃ is 3:2.
- The molar mass of NaN₃ is 65.01 g/mol.
Substituting all the known values to find the volume,
11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)
= 22.4 g.
22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.
Learn more about decomposition reaction,
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Answer:
T2 = 260 K
Explanation:
<em>Given data:</em>
P1 = 150.0 k Pa
T1 = (-23+ 273.15) K = 250.15 K
V1 = 1.75 L
P2 = 210.0 kPa
V2 = 1.30 L
<em>To find:</em>
T2 = ?
<em>Formula:</em>
<em>Calculation:</em>
T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)
T2 = 260 K
