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viva [34]
1 year ago
6

Answer the following Question Down Below...

Chemistry
1 answer:
bonufazy [111]1 year ago
5 0

The mass number of the atom is 21, the atomic number is 9, and the element is Fluorine. There are 9 protons, 9 electrons, 12 neutrons, and the elemental symbol is F.

<h3>Properties of an atom</h3>

For every atom:

  • Protons and neutrons are located in the nucleus and the addition of both equals the mass number of atoms.
  • Electrons are located outside the nucleus, in orbitals.
  • Neutral atoms have the same number of electrons and protons

In the diagram:

Number of electrons = 9

Number of protons = 9

Number of neutrons = 12

Mass number = 12 + 9

                      = 21

Atomic number = number of protons

                         = 9

Element with atomic number 9 = Fluorine

Symbol of the element = F

More on atoms can be found here: brainly.com/question/1566330

#SPJ1

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3 0
2 years ago
Solid sodium reacts violently with water, producing heat, hydrogen gas, and sodium hydroxide. How many molecules of hydrogen gas
Zinaida [17]

Answer: Number of molecules of hydrogen gas 6.32\times 10^{32}

Explanation:

2Na+2H_2O\rightarrow 2NaOH+H_2

Number of moles of sodium =\frac{\text{mass of sodium}}{\text{molar mass of sodium}}=\frac{48.7 g}{23 g/mol}=2.11mol

According to reaction , 2 moles of sodium produces 1 mole of hydrogen gas , then 2.11 mol of sodium will= \frac{1}{2}\times 2.11 mol of hydrogen gas that is 1.05 moles of hydrogen gas.

Number of molecules = N_A(\text{Avogadro number})\times moles of substance

Moles of hydrogen gas formed = 1.05 moles

Number of molecules of hydrogen gas = N_A\times moles of hydrogen gas

Number of molecules of hydrogen gas =6.022\times 10^{23} mole^{-1}\times 1.05 mole=6.32\times 10^{32}

8 0
2 years ago
Which of the following molecules can form hydrogen bonds? Group of answer choices NH3 NaH HI BH3 CH4
Len [333]

Answer:

NH₃

Explanation:

The hydrogen bond is a specially strong type of dipole-dipole interaction. For a hydrogen bond to occur, a molecule must have a hydrogen atom and a very electronegative atom, such as nitrogen, oxygen or fluorine. The hydrogen atom has a positive charge density while the heteroatom has a negative charge density.

<em>Which of the following molecules can form hydrogen bonds? </em>

NH₃ YES

NaH NO

HI NO

BH₃ NO

CH₄ NO

8 0
3 years ago
How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac
Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

,

• using the molar mass of Ca(OH)2 (74g/mol).

,

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

,

• using the molar mass of HNO3 (63.02g/mol).

4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3

So, 7.32g of HNO3 are required.

4 0
1 year ago
Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o
Gnom [1K]

Answer: The empirical formula for the given compound is C_5H_7N

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

C_xH_yN_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of CO_2=21.363mg=21.363\times 10^3g=21363g

Mass of H_2O=6.125g=6.125\times 10^3g=6125g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, \frac{12}{44}\times 21363=5826.27g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, \frac{2}{18}\times 6125=680.55 of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = \frac{485.52}{97.73}=4.96\approx 5

For Hydrogen  = \frac{680.55}{97.73}=6.96\approx 7

For Nitrogen = \frac{97.73}{97.73}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is C_5H_7N_1=C_5H_7N

7 0
2 years ago
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