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Answer:
Number of moles of hydrogen gas produced when 15.3 g of sodium reacts with water = 0.333 moles of hydrogen gas
Explanation:
The reaction between sodium metal and water is given by the chemical equation below:
2Na(s) + 2H₂O(l) ------> 2NaOH(aq) + H₂(g)
From the equation of reaction above, 2 moles of sodium reacts with 1 mole of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.
mole ratio of sodium and hydrogen gas is 2:1
molar mass of sodium =23 g/mol:
number of moles of sodium present in 15.3 g = mass/molar mass
number of moles of sodium present in 15.3 g = 15.3 g/ 23 g/mol = 0.665 moles
number of moles of hydrogen gas produced = 0.665 * 1/2 = 0.333 moles
Therefore, number of moles of hydrogen gas produced when 15.3 g of sodium reacts with water is 0.333 moles
Almost all of the mass (more than 99%) of an atom is contained in the dense nucleus. An atomic nucleus is much, much smaller than an atom. The cloud of electrons that "orbit" the nucleus and define the "size" of an atom is roughly100,000 times<span> as large as that atom's nucleus!</span>