Answer:
This question is incomplete, however, the unknown compound can be inferred to be "Lithium Bromide"
Explanation:
The unknown compound firstly is said to be an ionic compound. An ionic/electrovalent compound is a compound in which it's constituent ions transfer/receive electron(s). They are mostly made of group 1 and group 7 elements. Examples include NaCl, NaF, LiF and KCl.
Also, the ion (metallic ion) that produces a red flame test colour in a flame test is the <u>Lithium ion (Li⁺).</u> Also, when dissolved in water or hexane, the only halogen that produces a red/orange colour is bromine. Hence, the unknown ionic compound can be inferred to be Lithium Bromide.
From the group I A of the periodic table of the element can the chemist infer the element.
Answer:
Well, electrons can be converted into a atomic number so if SE atomic number is 34 that means it has 34 electrons. AI has a atomic number of 13 meaning it has 13 electrons. So the difference is that SE has more electrons then AI.
Answer:
Molten lead bromide, PbBr 2(l), is an electrolyte. During electrolysis: Pb 2+ ions gain electrons at the cathode and become Pb atoms. Br - ions lose electrons at the anode and become Br atoms, which pair up to form Br 2 molecules.
Explanation:
hope it helps
