Given:
Diprotic weak acid H2A:
Ka1 = 3.2 x 10^-6
Ka2 = 6.1 x 10^-9.
Concentration = 0.0650 m
Balanced chemical equation:
H2A ===> 2H+ + A2-
0.0650 0 0
-x 2x x
------------------------------
0.065 - x 2x x
ka1 = 3.2 x 10^-6 = [2x]^2 * [x] / (0.065 - x)
solve for x and determine the concentration at equilibrium.
PV=nRT
P=nRT/V
P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm
Answer:
A) 29.9g
Explanation:
first find the weight of 1 staple.
then multiply with 225
A mole of an element refers to 6.02e23 atoms so they would have the same amount of atoms
The answer is A, you winn not find carbon dioxide in ur pee lol I hope this helps out, have an amazing day!!
