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Pepsi [2]
3 years ago
9

The pressure exerted on a 240 ml sample of hydrogen gas at constant temperature is increased from 325 mmhg to 550 mm hg, what wi

ll be the final volume of the sample
Chemistry
1 answer:
jok3333 [9.3K]3 years ago
4 0
The  final  volume  of  the  sample  is calculate  using  boyles  law  formula 
that  is  P1V1=P2V2
V1 =  240  ml
P1= 325  nmmhg
P2=550  mmhg
V2=?
from  the  formula  above   V2  = P1V1/P2
=  240ml  x325mmhg /550  mmhg =   141.8 ml
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Determine the approximate amount of potassium hydrogen phthalate, KHP, that you will need to neutralize 6.00 ml of 0.100 M NaOH.
Sveta_85 [38]

Answer:

potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol

to get 1000 ml

Molar concentration = Mass concentration/Molar Mass

mass concentration = molar concentration x molar mass

mass concentration=0.1 M,

molar mass= 204.233 g/mol

so to get 1L

mass conc = 204.233 x 0.1

= 20.4233g  for 1L or 1000 ml

to get 6.00 ml

if 20.4233g is for 1000ml

then to 6.00 ml

= 20.4233 x 6 / 1000

= 0.123g for 6.00 ml

according to the equation below

NaOH(aq) + KHC8H4O4(aq) --> KNaC8H4O4(aq) + H2O(l)

number of moles of NaOH is equal to that of KHP

so the same amount will be needed too, which is

= 0.123g

6 0
2 years ago
Carbon dioxide is a colorless odorless gas why is it considered a pollutant?
WARRIOR [948]

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Carbon dioxide with other gases acts like a blanket of Earth which absorbs infrared radiations emitted from the sun and thus, preventing the escaping of these rays into the outer space which results in the gradual heating of Earth's surface and atmosphere i.e. increase in temperature of Earth. This process is known as Global Warming.

Hence, carbon dioxide is responsible for the increase in warming of the atmosphere i.e. option (D).



7 0
3 years ago
Read 2 more answers
A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to
grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0
3 years ago
In a physical change of matter,​
mel-nik [20]

Answer: C. no new substances are formed<span>
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<span>In the physical change of matter, there is no new substance that is formed. It is only the appearance of the matter that is being changed and not its chemical composition. Cutting, tearing and grinding are only some of the examples that exhibit physical change. </span></span>

5 0
2 years ago
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B) Which term is defined as a measure of the average kinetic energy of the particles in a sample of matter?
kogti [31]

Entropy is also defined as a measure of the average kinetic energy of particles in a sample of matter.

6 0
2 years ago
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