Answer:
6 A
Explanation:
First of all, we need to calculate the equivalent resistance of the circuit. The three resistors are connected in parallel, so their equivalent resistance is given by:
![\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}=\frac{1}{120 \Omega}+\frac{1}{60 \Omega}+\frac{1}{40 \Omega}=\frac{3+2+1}{120 \Omega}=\frac{6}{120 \Omega}\\R_T = \frac{120}{6} \Omega](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR_T%7D%3D%5Cfrac%7B1%7D%7BR_1%7D%2B%5Cfrac%7B1%7D%7BR_2%7D%2B%5Cfrac%7B1%7D%7BR_3%7D%3D%5Cfrac%7B1%7D%7B120%20%5COmega%7D%2B%5Cfrac%7B1%7D%7B60%20%5COmega%7D%2B%5Cfrac%7B1%7D%7B40%20%5COmega%7D%3D%5Cfrac%7B3%2B2%2B1%7D%7B120%20%5COmega%7D%3D%5Cfrac%7B6%7D%7B120%20%5COmega%7D%5C%5CR_T%20%3D%20%5Cfrac%7B120%7D%7B6%7D%20%5COmega)
And now we can use Ohm's law to find the current in the circuit:
![V=R_T II=\frac{V}{R_T}=\frac{120 V}{\frac{120}{6}\Omega}=6 A](https://tex.z-dn.net/?f=V%3DR_T%20II%3D%5Cfrac%7BV%7D%7BR_T%7D%3D%5Cfrac%7B120%20V%7D%7B%5Cfrac%7B120%7D%7B6%7D%5COmega%7D%3D6%20A)
What does thrice mean not being mean or anything just saying so I can help with the question
The frequency of the wave is 6800 Hz
<u>Explanation:</u>
Given:
Wave number, n = 20
Speed of light, v = 340 m/s
Frequency, f = ?
we know:
wave number = ![\frac{frequency}{speed of light}](https://tex.z-dn.net/?f=%5Cfrac%7Bfrequency%7D%7Bspeed%20of%20light%7D)
![20 = \frac{f}{340 m/s} \\\\f = 20 X 340 s^-^1\\\\f = 6800 Hz](https://tex.z-dn.net/?f=20%20%3D%20%5Cfrac%7Bf%7D%7B340%20m%2Fs%7D%20%5C%5C%5C%5Cf%20%3D%2020%20X%20340%20s%5E-%5E1%5C%5C%5C%5Cf%20%3D%206800%20Hz)
Therefore, the frequency of the wave is 6800 Hz