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photoshop1234 [79]
3 years ago
5

What is transmitted by all waves? energy mass matter sound

Physics
2 answers:
disa [49]3 years ago
7 0

Answer: energy

Explanation: A wave is a disturbance that transfers energy as it travels through medium.

Vikentia [17]3 years ago
3 0

Answer:

Option (1)

Explanation:

All waves can carry energy, and this energy can be high or low. The waves that carry high energy are commonly known as the high energy waves such as X-rays and gamma rays. On the other hand, those waves that can carry low energy are considered to be low-energy waves such as radio waves.

There are two types of waves that carry energy, namely the electromagnetic wave and the longitudinal waves.

In the case of electromagnetic waves, the energy is transported in the form of vibrations of both electric as well as magnetic field. Whereas, in the case of longitudinal waves such as sound waves, this energy is carried through a medium in which the sound propagates.

Thus, the correct answer is option (1).

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Tony waits for the spring tide to bring the best surfing waves in his area. He knows that the moon affects the tides, so which m
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What is the relationship between speed and kinetic energy?
kobusy [5.1K]

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Kinetic energy depends on the velocity of the object squared. This means that when the velocity of an object doubles, its kinetic energy quadruples.

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5 0
3 years ago
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole.
Fiesta28 [93]

Answer:

6.0 m/s

Explanation:

According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.

Therefore, we can write:

KE_i+PE_i =KE_f+PE_f

or

\frac{1}{2}mu^2+0=\frac{1}{2}mv^2+mgh

where:

m is the mass of the athlete

u is the initial speed of the athlete (at the bottom)

0 is the initial potential energy of the athlete (at the bottom)

v = 0.80 m/s is the final speed of the athlete (at the top)

g=9.8 m/s^2 is the acceleration due to gravity

h = 1.80 m is the final height of the athlete (at the top)

Solving the equation for u, we find the initial speed at which the athlete must jump:

u=\sqrt{v^2+2gh}=\sqrt{0.80^2+2(9.8)(1.80)}=6.0 m/s

4 0
3 years ago
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