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Pavel [41]
3 years ago
14

Can A magnet can be changed by hitting it hard or exposing it to heat.

Chemistry
1 answer:
Ainat [17]3 years ago
6 0
Well, a magnet could DEFINITELY change if it gets exposed to heat, because you could melt the metal and change its shape.
If you hit it hard though, it wouldn't make much of a difference because the magnet is metal, so you'll probably just chip it or leave a dent.
Hope this helps ;)
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A 0.43g samle of KHP required 24.11cm of NaOH for neutralization. Calculate the molarity of NaOH
expeople1 [14]

Answer:

0.083 M

Explanation:

We'll begin by calculating the number of mole in 0.43 g of KHP (potassium hydrogen phthalate, C₈H₅O₄K). This is can be obtained as follow:

Mass of C₈H₅O₄K = 0.43 g

Molar mass of C₈H₅O₄K = (8×12) + (5×1) + (16× 4) + 39

= 96 + 5 + 64 + 39 = 204 g/mol

Mole of C₈H₅O₄K =?

Mole = mass / molar mass

Mole of C₈H₅O₄K = 0.43 / 204

Mole of C₈H₅O₄K = 0.002 mole

Next, we shall determine the number of mole of NaOH required to react with 0.43 g (i.e 0.002 mole) of KHP. This can be obtained as follow:

C₈H₅O₄K + NaOH → C₈H₄O₄KNa + H₂O

From the balanced equation above,

1 mole of KHP reacted with 1 mole of NaOH.

Therefore, 0.002 mole of KHP will also react with 0.002 mole of NaOH.

Next, we shall convert 24.11 cm³ to L. This can be obtained as follow:

1000 cm³ = 1 L

Therefore,

24.11 cm³ = 24.11 cm³ × 1 L / 1000 cm³

24.11 cm³ = 0.02411 L

Finally, we shall determine the molarity of NaOH. This can be obtained as follow:

Mole of NaOH = 0.00 2 mole

Volume = 0.02411 L

Molarity of NaOH =?

Molarity = mole /Volume

Molarity of NaOH = 0.002 / 0.02411

Molarity of NaOH = 0.083 M

3 0
3 years ago
In a solution of salt and water which component is the salute A salt B water C speaker D oxygen
Wewaii [24]
Hi thereeeeeeeeeee! salt is ur answer !
8 0
3 years ago
Read 2 more answers
Please select the best answer and click "submit."
vladimir1956 [14]
When it comes to physical changes like phase changes, there are two types of heat energy: sensible heat and latent heat. Sensible heat is the heat absorbed/released when you heat the substance but it doesn't change phase. An example would be heating lukewarm water. The substance is liquid all throughout. Latent heat, on the other hand, is the heat absorbed/released when there is a phase change. An example would be boiling water, because it changes liquid to vapor. 

Hence, for freezing liquid, you use the latent heat, specifically the heat of fusion. The answer should be

2.5 g * (1 mol/18.02 g) * 6.03 kJ/mol = 0.84 kJ/mol

The answer is not in the choices. You only use Hvap if you boil water.
5 0
3 years ago
The equilibrium constant for the reaction sr(s) + mg2+(aq) ⇌ sr2+(aq) + mg(s) is 3.69 × 1017 at 25°c. calculate e o for a cell m
frutty [35]
We are going to use this formula:

E° = 0.0592/ n * ㏒K

when E° is the standard state cell potential

and n is number of moles of electrons transferred in the balanced equation

for the reaction of the cell.

Sr(s) + Mg2+ (aq) ↔ Sr2+(aq) + Mg(s)

we can get it by using the given balanced equation, we here have 2 electrons

transferred so, n = 2 

and K the equilibrium constant = 3.69 x 10^17

so, by substitution:

∴ E° = 0.0592 / 2 * ㏒ (3.69 x 10^17)

        = 0.52 V
8 0
3 years ago
which of the following halides reacts more slowly in an SN1 reaction: 5-chloro-1,3-cyclopentadiene or 7-chloro-1,3,5-cycloheptat
Rudiy27

Answer:

5-chloro-1,3-cyclopentadiene

Explanation:

5-chloro-1,3-cyclopentadiene will react more slowly in an SN1 reaction. ( i.e. No reaction as the product is unstable ) attached is the representation of the rate of reaction of both Halides which shows that 5-chloro-1,3-cyclopentadiene reacts the slowest .

Also During SN1 reaction Carbocation is formed .

Attached below is the solution explanation

8 0
3 years ago
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