At s.t.p, the volume of a gas =22.4dm³
Talking the problem,
At 1atm, 273K the volume =7 moles *22.4dm³/mol
At 323K, 2.90atm, volume =?
The combined gas equation
P1v1/T1=P2v2/T2
P1=1atm
P2=2.9atm
T1=273K
T2=323K
V1=156.8dm³
Therefore,
1*156.8dm³/273=2.9atm*V2/323
V2=(156.8dm³*323K)/(273K*2.9atm)
= 64dm³
Answer:
Explanation:
Raoult's law is a tool that allows to determine vapour pressure of solutions. The formula is:
<em>(1)</em>
Where
P is Pressure of solution and solvent and X is mole fraction.
Moles of solute and solvent are:
Biphenyl:
11.5g×(1mol /154.21g) = <em>0.0746mol</em>
Benzene
31.9g×(1mol /78.11g) = <em>0.408mol</em>
Mole fraction of benzene is:
= <em>0.846</em>
Replacing in (1):


I hope it helps!
Pressure does not affect the voltage produced in a voltaic cell.