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The prefix "iso" is used when all carbons except one form a continuous chain. ... The prefix "sec" or "s" is used when the functional group is bonded to a secondary carbon.
Answer:
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Answer:
Because the optimal range of buffering for a formic acid potassium formate buffer is 2.74 ≤ pH ≤ 4.74.
Explanation:
Every buffer solution has an optimal effective range due to pH = pKa ± 1. Outside this range, there is not enough acid molecules or conjugate base molecules to sustain the pH without variation. There is a certain amount of both molecules that has to be in the solution to maintain a pH controlled.
Being for the formic acid the pKa 3.74, the optimal effective range is between 2.74 and 4.74. Upper or lower these range a formic acid/potassium formate buffer does not work.
Answer:
1-<u>Pentanol </u>has the highest boiling point.
Explanation:
Boiling points of given compounds are as follow,
1) 2-Pentanone = 101 °C
2) 1-Pentanol = 138 °C
3) Pentane = 36.1 °C
4) Pentanal = 103 °C
Pentanol has greatest boiling point as compare to others because it involes a strongest intermolecular interactions called as hydrogen bond interactions. Remaining compounds lack the direct attachement of hydrogen to most electrnegative atom like oxygen which is present in 1-Pentanol.
The temperature of the gas sample is 813 K.
<u>Explanation:</u>
We have to use the ideal gas equation to find the temperature of the gas sample.
The ideal gas equation is PV = nRT
Pressure, P = 429 mm Hg = 0.56 atm
Volume, V = 560 mL = 0.56 L
R = gas constant = 0.08205 L atm mol⁻¹K⁻¹
Mass = 0.211 g
Molar mass of carbon di oxide = 44.01 g / mol
Moles, n = 
= 0.0047 mol
Now, we have to plugin the above values in the above equation, we will get the temperature as,
T = 
= 813 K
So the temperature of the gas sample is 813 K.
