Question

A 0.211 g sample of carbon dioxide, CO2, has a volume of 560 mL and a pressure of 429 mmHg whats the temperature of the gas in Kelvin

Answer 1

The temperature of the gas sample is 813 K.

Explanation:

We have to use the ideal gas equation to find the temperature of the gas sample.

The ideal gas equation is PV = nRT

Pressure, P = 429 mm Hg = 0.56 atm

Volume, V = 560 mL = 0.56 L

R = gas constant = 0.08205 L atm mol⁻¹K⁻¹

Mass = 0.211 g

Molar mass of carbon di oxide = 44.01 g / mol

Moles, n = $\frac{given mass}{molar mass} = \frac{0.211 g}{44.01 g/mol}$

              = 0.0047 mol

Now, we have to plugin the above values in the above equation, we will get the temperature as,

$T= \frac{PV}{nR}$

T = $\frac{0.56 \times 0.56}{0.08205 \times 0.0047}$

 = 813 K

So the temperature of the gas sample is 813 K.