Answer:
Explanation:
functional groups are specific substituents or atoms within molecules that brings about chemical reactions of those molecules. There is the same or similar chemical reaction in compounds with the same functional groups.
1.)The functional group in Alkyl halides is halogen atom whille
The functional group in Alcohols have
is OH group. There is a double bond in HX or an HOH molecules.
2.)The functional group of carboxylic acid is an organic compound is carboxyl functional group.While The functional group in amine contains a basic nitrogen atom with a lone pair of electrons.
3.)The functional group in ester is a carboxylic acid derivative that is analogous to the Amides
4.) A carboxylic acid has carboxyl functional group. However the hydrogen of the hydroxyl group is can be ionized. In an ester, there is a replacement of hydrogen of acarboxylic acid group by an alkyl group
To answer this question, we should give the standard free energy change of ATP to ADP conversion that is equal to 30.5 kJ/mol ATP. In this case, 2400 kcal is equal to 10041. 6 kJ. Hence, the mol of ATP produced is 329.23 mol ATP or equal to 166.93 kg ATP.
The main factor is the size of the moon. which is small compared to the earth, meaning that the moon has less gravity, and more gas is allowed to escape the surface, Which basically means theres no atmosphere.
Answer:
Explanation:
There are two ways of looking at this problem. The first way, slightly more advanced, is to understand that the carbocation formed is an intermediate in this reaction: it is formed in one step and consumed in the subsequent step.
Secondly, we have hydroxide involved as our reactant, so it should be our second reactant in the second bimolecular step.
Thirdly, the product formed would be a combination of the anion and cation, one of our products, this means we have the following second step:
Another way is to verify this knowing that by adding all of the steps should yield a net equation, notice if we add the two steps together (reactants on one side and products on the other), we obtain:
Notice that the intermediate carbocation cancels out on both sides to yield the final net equation:
This means we have the correct second step.
