How many atoms are in 16.67g of Calcium Nitrate?

2 answers:

5 0

<span>5.506x10^23 atoms First, determine the molar mass of Calcium Nitrate [ Ca(NO3)2 ]. Look up the atomic weights of the involved elements. Atomic weight calcium = 40.078 Atomic weight nitrogen = 14.0067 Atomic weight oxygen = 15.999 Molar mass Ca(NO3)2 = 40.078 + 2 * 14.0067 + 6 * 15.999 = 164.0854 g/mol Determine the number of moles of Ca(NO3)2. 16.67 g / 164.0854 g/mol = 0.101593439 mol Now multiply by the number of atoms in Ca(NO3)2 which is 9. So 9 * 0.101593439 = 0.914340947 Finally, multiply by avogadro's number. Giving: 0.914340947 * 6.0221409x10^23 = 5.50629001x10^23 Round the result to 4 significant figures, giving 5.506x10^23 atoms.</span>

Marta_Voda [28]3 years ago

4 0

The number of atoms in calcium nitrate can easily be found by multiplying a given mole of Calcium Nitrate by Avogadro's number since each mole of a substance contains 6.03 × 10²³.

Now, mol of Ca(NO₃)₂ = mass of Ca(No₃)₂ ÷ molar mass of Ca(NO₃)₂
mol of Ca = 16.67 g ÷ [(40 × 1) + (14 × 2) + (16 × 3 × 2) g/mol
mol of Ca = 0.1016 mol

⇒ atoms of Ca(NO₃)₂ = 0.0812 mol × (6.02 × 10²³ atoms/mole)
= 6.12 × 10²² atoms

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But how to get there?

Let's start with simple explanation of what exactly is cellular respiration.

Cellular respiration is a multistage biochemical oxidation process of organic substances when prime product is energy (ATP - adenosine triphosphate) and other are released waste products. Cellular respiration takes place even if other metabolic processes are stopped, but cellular respiration may differ in particular organism groups.Some reactions during whole process of cellular respiration are similar in all types of living organisms.

Cellular respiration is prime indication of declining living processes.Only viruses which are on the edge of living organism and chemical particle are not performing cellular respiration.But to the point :P

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so for now we have just part of the equation:

$C_{6}H_{12}O_6+O_{2}\Rightarrow$

But what would be on the right hand side?

It's quite simple, remember equation of full combustion? If we want to burn something we need oxygen like in the equation, so the product of this equation would be carbon dioxide, water and of course energy (ATP).Carbon dioxide formula looks like this:

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As a reminder water formula:

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Full formula would look like that:

$C_{6}H_{12}O_6+O_{2}\Rightarrow\ CO_{2}+H_{2}O+energy$

But still as you see this equation is unbalanced, after balancing it would like that:

$C_{6}H_{12}O_6+6O_{2}\Rightarrow 6CO_{2}+6H_{2}O+energy$

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