<u>The dependent and independent quality in the given situation:</u>
The given situation is that a long-distance telephone call cost increases with the number of minutes of the call. The two variables are dependent and independent.
The independent variable here in the given situation is the number of minutes of the call since it can be changed as much as we want
The dependent variable is the cost of the long-distance call as it relies on the number of minutes of the call. The cost increases when the number of minutes increases.
Answer: See step by step
Step-by-step explanation: For A my 15 statements are.
- It has 3 triangles inside it, ACD, ADC, and ABC
- It has 2 right triangles, and 1 isoceles
- AC≅AB
- CD≅DB
- D is midpoint of CB
- AD⊥CB
- Angle CDA=90 degrees
- Angle BDA equal 90 degrees
- AD≅AD
- ΔCDA≅ΔBDA by any congruence theorem, (SSS, SSA,AAS,ASA, HL)
- + =
12.+ =
13. Triangle ABC has a max of 180 degrees.
14. We can rotate this triangle 180 degrees and it will coincide.
15. We can reflect triangle ACD over vertical line ACD and it will be congruent to ABD.
2. We use pythagorean theorem since it has a right angle.
+ = Let plug it in.
+=
1600+ b^2=2025
b^2=424
sqr root of 425 is about 21. Now let find the perimeter.
AB is 45, Since BD+DC=CB, and they are congruent they are equal so 21+21=42 and AC is congruent to AB so it is 45. So the perimeter is 132.
For 3. Start at the orgin, then go up 5 on the y-axis so you should be at (0,5)
Then use the rise over run method to graph it. go left -3 and and up 1. Keep doing that 2 more times then draw a straight line.
Your 3 point should be
(0,5)
(1,2)
(2,1)
2.674 with all of them added together. If you include sig figs it would be 2.7
Answer:
x = 17
Step-by-step explanation:
To solve this equation, we can illustrate the algebraic concepts being employed and solve for the variable.
3(x - 4) = 2x + 5 Distribute the 3 into the parentheses.
3x - 12 = 2x + 5 Subtract 2x from both sides of the equation to combine like terms.
x - 12 = 5 Add 12 to both sides of the equation.
x = 17