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4 years ago

5

How can u use physics in the real world

1 answer:

Blizzard [7]4 years ago

3 0

Physics can be used in a variety of ways, a specific example would be rollercoaster. Physics can be used to determine the speed at which a rollercoaster can travel without going off the rails or when it needs to begin to slow down to make a sharp turn.

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What is the frequency of a wave if the speed of the wave is 7.9m/s and the wavelength is 3.1m?

Tpy6a [65]

Answer:

<h2>2.55 Hz</h2>

Explanation:

The frequency of the wave given it's velocity and wavelength can be found by using the formula

$f = \frac{c}{ \lambda} \\$

where

c is the velocity of the wave in m/s

$\lambda$ is the wavelength in m

From the question

c = 7.9 m/s

$\lambda$ = 3.1 m

We have

$f = \frac{7.9}{3.1} = 2.548387... \\$

We have the final answer as

<h3>2.55 Hz</h3>

Hope this helps you

6 0

3 years ago

Will give brainiest 8th grade physics

Iteru [2.4K]

Answer:

B

Explanation:

Hope this helped!

7 0

3 years ago

A shopper weighs 4.00 kg of apples on a supermarket scale whose spring obeys Hooke's law and notes that the spring stretches a d

Irina-Kira [14]

Answer:

a) 0.040625 m

b) 5.02272 J

Explanation:

k = Spring constant

x = Stretched length

F = Force

a)

$F=kx\\\Rightarrow k=\frac{F}{x}\\\Rightarrow k=\frac{4\times 9.81}{0.025}\\\Rightarrow k=1569.6\ N/m$

$F=kx\\\Rightarrow x=\frac{F}{k}\\\Rightarrow x=\frac{6.5\times 9.81}{1569.6}\\\Rightarrow x=0.040625\ m$

Extension of the spring would be 0.040625 m

b) Work done in a spring

$W=\frac{1}{2}kx^2\\\Rightarrow W=\frac{1}{2}\times 1569.6\times 0.08^2\\\Rightarrow W=5.02272\ J$

The work done by the shopper to stretch this spring a total distance of 8.00 cm is 5.02272 J

4 0

3 years ago

Momentum = ___________.

posledela

The answer must be a mass x velocity

4 0

3 years ago

In a circuit with one 12.0 resistor, a current of 0.500 A is flowing. This circuit is powered by a single

Juliette [100K]

Answer:

6 V

Explanation:

In a circuit, the relationship between voltage, current and resistance is given by Ohm's law:

$V=RI$

where

V is the voltage

R is the resistance

I is the current

In this circuit, we have

$R=12.0\Omega$ is the resistance

I = 0.500 A

so we can find the voltage of the battery by using Ohm's law:

$V=(12.0 \Omega)(0.500 A)=6 V$

4 0

3 years ago