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Makovka662 [10]
3 years ago
9

Marble Slab Creamery is creating a cone-shaped paper wrapper for its new green Baby Yoda waffle cone. The wrapper should have a

radius of 5 cm and a slant height of 10 cm. One location wants to offer the cones a weekend earlier, so they plan to make the cone-shaped wrappers for first 25 waffle cones sold that Saturday. About how many square cm of wrapper paper will they need? (Round up to the nearest cm.)
Mathematics
1 answer:
mote1985 [20]3 years ago
3 0

Answer:

3927 cm² wrapping paper will be required.

Step-by-step explanation:

Lateral surface area of a cone shaped wrapper = πrl

where, r = radius of the waffle cone

and l = slant height of the cone

It has been given in the question, radius 'r' = 5cm

and lateral height 'l' = 10 cm

Lateral surface area of the cone = π(5)(10)

                                                      = 50π

                                                      = 157.08 cm²

If they plan to make 25 waffles then wrapper paper required

= 25×157.08

= 3927 cm²

Therefore, 3927 cm² wrapping paper will be required.

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Answer:

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Step-by-step explanation:

we would like to expand the following logarithmic expression:

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remember the multiplication logarithmic indentity given by:

\displaystyle \rm  \log( \alpha  \times  \beta ) \iff  \log( \alpha ) +  \log( \beta )

so our given expression should be

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\displaystyle   5\log( {x}^{}   )  +   2 \log( {y}^{} )

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3 years ago
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No, the given point does not satisfy the inequality

<em><u>Solution:</u></em>

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Let us substitute the given point (x, y) = (-2, 1) in given inequality

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