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Makovka662 [10]
2 years ago
9

Marble Slab Creamery is creating a cone-shaped paper wrapper for its new green Baby Yoda waffle cone. The wrapper should have a

radius of 5 cm and a slant height of 10 cm. One location wants to offer the cones a weekend earlier, so they plan to make the cone-shaped wrappers for first 25 waffle cones sold that Saturday. About how many square cm of wrapper paper will they need? (Round up to the nearest cm.)
Mathematics
1 answer:
mote1985 [20]2 years ago
3 0

Answer:

3927 cm² wrapping paper will be required.

Step-by-step explanation:

Lateral surface area of a cone shaped wrapper = πrl

where, r = radius of the waffle cone

and l = slant height of the cone

It has been given in the question, radius 'r' = 5cm

and lateral height 'l' = 10 cm

Lateral surface area of the cone = π(5)(10)

                                                      = 50π

                                                      = 157.08 cm²

If they plan to make 25 waffles then wrapper paper required

= 25×157.08

= 3927 cm²

Therefore, 3927 cm² wrapping paper will be required.

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Answer:

(i) see first attached diagram

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Step-by-step explanation:

A bearing is the angle in degrees measured clockwise from north.

<u />

<u>Part (i)</u>

see first attached diagram

<u>Part (ii)</u>

The angles marked in blue on the second attached diagram are Consecutive Interior Angles.  In this case they add to 180° as the North lines are parallel.

The sum of angles around a point is 360°

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To calculate the distance between Q and R (marked in red on the attached diagram), use the cosine rule.

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<u>Part (iii)</u>

We need to find the angle marked in green on the third attached diagram.

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