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3 years ago

HELP ASAP!! WILL GIVE BRAINLIEST ❤️

Mathematics

1 answer:

yan [13]3 years ago

4 0

Answer:

the slope is negative

Step-by-step explanation:

because they both have negative signs so that would make the line go down

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8( 3x + 3) = 3(9x-9)

Helen [10]

Answer:

x = -15

Step-by-step explanation:

x equals negative 15

7 0

3 years ago

Solve the compound inequality 2x − 3 < 7 and 5 − x ≤ 8. A. x ≥ 3 and x < 2 B. x ≥ 3 and x < 5 C. x ≥ −3 and x < 2 D.

Blizzard [7]

Given:

The compound inequality $2x-3 < 7$ and $5-x \leq 8$ .

To find:

The solution for the given compound inequality

Solution:

We have, compound inequality $2x-3 < 7$ and $5-x \leq 8$ .

For $2x-3 < 7$ ,

Add 3 on both sides.

$2x < 7+3$

$2x < 10$

Divide 2 on both sides.

$x< 5$ ...(i)

For $5-x \leq 8$ ,

Subtract 5 from both sides.

$-x \leq 8-5$

$-x \leq 3$

Divide both sides by -1. So, the sign of inequality is changed.

$x \geq -3$ ...(ii)

Using (i) and (ii), we get the solution of given compound inequality as

$x \geq -3$ and $x< 5$

Therefore, the correct option is D.

6 0

3 years ago

Somebody Please solve this question without using L Hospital rule.<br><br>Evaluate if:

iren [92.7K]

Answer:

1/2

Step-by-step explanation:

Given that,

$\lim_{n \to 1} (\dfrac{1+\cos\pi x}{\tan^2\pi x})$

Using L Hospital's rule to find it :

$\lim_{n \to a} \dfrac{f(x)}{g(x)}= \lim_{n \to a} \dfrac{f'(x)}{g'(x)}$

We have,

a = 1, $f(x)=1+\cos\pi x, \ \ g(x)=\tan^2\pi x$

$f'(x)=\dfrac{d}{dx}(1+\cos\pi x)\\\\=-\pi \sin \pi x\ .....(1)$

$g'(x)=\dfrac{d}{dx}(\tan^2\pi x)\\\\=2\tan\pi x\times \sec^2\pi x\times \pi\ .....(2)$

From equation (1) and (2) :

$\lim_{n \to 1} \dfrac{f(x)}{g(x)}= \lim_{n \to 1} \dfrac{-\pi \sin\pi x}{2\tan \pi x\times \sec^2\pi x \times \pi}\\\\\lim_{n \to 1} \dfrac{-\pi \sin\pi x}{2\tan \pi x\times \sec^2\pi x \times \pi}\\\\=\lim_{n \to 1} \dfrac{-1}{2}\times\cos^3\pi x\\\\=\dfrac{-1}{2}\times \cos^3\pi \\\\=\dfrac{1}{2}$

So, the value of the given function is 1/2.

7 0

3 years ago

A triangle weighs 3 grams and a circle weighs 6 grams. Find the weight of a square in Hanger A and the weight of a pentagon in H

Zanzabum

Answer:

Equation of Hanger A:

x + y = z

z = 9 grams

Equation for hanger B

x + y = p

p = 9 grams

Step-by-step explanation:

Note: This question is not complete, and lacks necessary data to answer this question. But for the sack of concept, we wil be solving this question using our own data.

Data given:

Triangle weight = 3 grams

Circle weight = 6 grams

There are two hangers A and B.

We have to find weight of the square in Hanger A and weight of the pentagon in Hanger B.

So, for your understanding I have drawn the two hangers A and B. In A we have triangle and circle on the LHS and the square on the right. On the other hand, we have pentagon on the right and triangle and circle.

Sketch is attached in the attachment.

Let's suppose: Hanger A is balanced, So,

Triangle weight = 3 grams = x

Circle weight = 6 grams = y

weight of the pentagon in Hanger B = p

weight of the square in Hanger A = z =?

So,

Equation of Hanger A:

x + y = z

z = 3 + 6

z = 9 grams = weight of the square in Hanger A

Similarly for Hanger B.

Equation for hanger B

x + y = p

p = 3 + 6

p = 9 grams

6 0

3 years ago

What dose 5t=25 mean?

topjm [15]

5t = 25
You need to isolate the variable by dividing each side by 5
So
t = 5

5 0

3 years ago

Read 2 more answers