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Afina-wow [57]
3 years ago
6

A gas occupies 200 mL at -73.0°C. To have the same gas occupy 300 mL, should the temperature be increased or decreased? What is

the new temperature in Kelvins? K
Physics
2 answers:
Tcecarenko [31]3 years ago
8 0

A gas occupies 200 mL at -73.0 degrees Celsius. To have the same gas occupy 300 milliliters, the temperature should be increased. 300K is the new temperature in Kelvins.

ValentinkaMS [17]3 years ago
7 0
<span>(PV)/T = (PV)/T. You can exclude the pressures since they are not mentioned. This means that V1/T1 = V2/T2. Kelvin is C + 273. Sooo, solving for T2=(V2T1)/V1. T2=(0.300L*200K)/0.200L=300K. NOTE: Volume should be in Liters, Temp in Kelvin, Pressure in atm (not used here).</span>
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If half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration it can achieve o
Scilla [17]

Answer:

Maximum acceleration will be equal to 3.43m/sec^2

Explanation:

We have given coefficient of kinetic friction \mu _k=0.7

And coefficient of static friction \mu _s=1

Acceleration due to gravity g=9.8m/sec^2

When truck moves maximum force will be equal to F=\mu _kmg

It is given that half of the weight is supported by its drive wheels

So force required =\frac{\mu _kmg}{2}

From newtons law maximum acceleration will be equal to a=\frac{\frac{\mu _kmg}{2}}{m}=\frac{\mu _kg}{2}=\frac{0.7\times 9.8}{2}=3.43m/sec^2

8 0
4 years ago
Which of these is an example of energy transfer by radiation?
andrezito [222]

Answer:

Hands rubbed together to become warm

6 0
3 years ago
Read 2 more answers
A 90kg cannon fires 100kg shell with muzzle velocity of 75m/s. Calculate the recoil velocity of the cannon relative to the groun
Gala2k [10]

Answer: 83.8 m/s

Explanation:

momentum of shell = momentum of cannon

M(s) × V(s) = M(c) × V(c)

M(s) = mass of shell, V(s) = velocity of shell

M(c) = mass of cannon, V(c) = velocity of cannon

100kg × 75m/s = 90kg × V(c)

7500 = 90 × V(c)

7500 ÷ 90 = V(c)

83.3 = V(c)

5 0
3 years ago
A bicycle starts at 2.5m/s and accelerates along a straight path to a speed of 12.5m/s in a time of 4.5 seconds. What is the bic
zalisa [80]

Answer:

The bicyclist's acceleration is 2.2m/s^2

Explanation:

Given

u = 2.5m/s ---- Initial Velocity

v = 12.5m/s ---- Final Velocity

t = 4.5s ---- Time

Required

Determine the acceleration

This will be solved using the first equation of motion

v = u + at

Substitute values for v, u and a

12.5 = 2.5 + a * 4.5

12.5 = 2.5 + 4.5a

Collect Like Terms

4.5a = 12.5 - 2.5

4.5a = 10.0

Solve for a

a = 10.0/4.5

a = 2.2m/s^2 ---- (approximated)

<em>Hence, the bicyclist's acceleration is 2.2m/s^2</em>

3 0
3 years ago
Which of the following statements are true?
Virty [35]

Answer:

The true statements are;

a.The decrease in the amplitude of an oscillation caused by dissipative forces is called damping

b.An oscillation that is maintained by a driving force is called forced oscillation

Explanation:

To answer the question, we analyze each of the options as follows;

a.The decrease in the amplitude of an oscillation caused by dissipative forces is called damping.

The above statement is true as damped oscillation is one in which the amplitude is decreased by dissipative forces

b.An oscillation that is maintained by a driving force is called forced oscillation.

When a damped oscillator is allowed to oscillate by itself, it will stop eventually. However when a force is applied to maintain the oscillation the oscillation is then known as a forced oscillation

The above statement is true

c.In a mechanical system, the amplitude of an oscillation diminishes with time unless the lost mechanical energy is replaced.

The above statement is only true in damped oscillation system

d.The increase in amplitude of an oscillation by a driving force is called forced oscillation.

Forced oscillation, as described above, is one the maintains the oscillation of  damped oscillator, therefore, the above statement is not correct.

8 0
3 years ago
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