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Afina-wow [57]
3 years ago
6

A gas occupies 200 mL at -73.0°C. To have the same gas occupy 300 mL, should the temperature be increased or decreased? What is

the new temperature in Kelvins? K
Physics
2 answers:
Tcecarenko [31]3 years ago
8 0

A gas occupies 200 mL at -73.0 degrees Celsius. To have the same gas occupy 300 milliliters, the temperature should be increased. 300K is the new temperature in Kelvins.

ValentinkaMS [17]3 years ago
7 0
<span>(PV)/T = (PV)/T. You can exclude the pressures since they are not mentioned. This means that V1/T1 = V2/T2. Kelvin is C + 273. Sooo, solving for T2=(V2T1)/V1. T2=(0.300L*200K)/0.200L=300K. NOTE: Volume should be in Liters, Temp in Kelvin, Pressure in atm (not used here).</span>
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How many electrons does a neutral atom of the element oxygen have?
sesenic [268]

Answer:

8 electrons

Explanation:

Now you can figure out how many electrons, protons and neutrons Oxygen has: Atomic number (which is always the smaller of the two numbers) is 8. Hence 8 protons. Because the atom is neutral, there are also 8 electrons.

6 0
3 years ago
Which statement best describes the superposition principle?
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<h3><u>Answer;</u></h3>

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<h3><u>Explanation;</u></h3>
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6 0
4 years ago
If you were to measure the width of your lab manual with a meter stick, and then the length (roughly 50% longer), by what fracti
Leona [35]

Answer:

Explanation:

a )  Let breadth be L , then length will be 1.5 L

Since it is a meter scale , the least count is 1 m.m. So

maximum possible error in a measurement is 1 mm.

In both the measurement of length and breadth , absolute

uncertainty will be 1mm.

Hence there is no difference in  absolute uncertainty of their measurement.

b ) percent uncertainty in the measurement of length

\frac{1 mm}{1.5L\times1000} \times100

= 1 / 15L%

percent uncertainty in the measurement of breadth

\frac{1 mm}{L\times1000} \times100

1 / 10L%

In breadth it will be higher by

( 1/10L - 1/15L)/ 1/10L

= 1/3

c ) Uncertainty  in the measurement of R= 1 %

Area A = π R²

ΔA/A X100 = 2 X ΔR/R X 100

Percentage uncertainty in A = 2 X percentage uncertainty in R

= 2 X 1

=2 %

Therefore percentage  accuracy in the calculation of area

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7 0
3 years ago
A 15.5 kg block is pulled by two forces. The first is 11.8N at a 53.7 angle and the second is 22.9 N at a -15.8 angle. What is t
anygoal [31]

Answer:

α = 6.43° (Angle respect to the horizontal axis-x)

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces must be equal to the product of mass by acceleration.

Since we have two forces and we know their magnitudes and their directions, we can sum these into their X & y components, in this way we can find the resulting force and apply it in Newton's second law.

F1x = 11.8*cos(53.7) = 6.98 [N]

F1y = 11.8*sin(53.7) = 9.5 [N]

Now with the second force:

F2x = 22.9*cos (15.8) = 22.03 [N]

F2y = - 22.9*sin (15.8) = - 6.23 [N]

Now we sum the forces in the x and y axes:

Fx = F1x + F2x = 6.98 + 22.03 = 29.01 [N]

Fy = F1y + F2y = 9.5 -  6.23 = 3.27 [N]

Now using the Pythagorean theorem we can find the resulting force.

F = √(Fx² + Fy²)

F = √ (29.01)² + (3.27)²

F = 29.19 [N]

Using Newton's second law, we have:

F = m*a

where:

F = force = 29.19 [N]

m = mass = 15.5 [kg]

a = acceleration [m/s²]

a = 29.19/15.5

a = 1.88 [m/s²]

The direction of the acceleration is the same direction of the force, therefore we need to find the angle.

tan(α) = Fy/Fx

tan(α) = 3.27/29.01

α = tan⁻¹(0.1127)

α = 6.43° (Angle respect to the horizontal axis-x)

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