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borishaifa [10]
3 years ago
15

A student has a displacement of 304 m north in 180 s. What was the student's average velocity?

Physics
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

v = 1.69 m/s

Explanation:

Given that,

Displacement of the student is 304 m due North and it takes 180 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s

Hence, the student's average velocity is 1.69 m/s.

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What name is given to the condition of stability enabled by a set of processes such as those involved in the maintenance of inte
BabaBlast [244]

Answer:

C. Metabolism

Explanation:

Although it is a process that we cannot visualize, we feel it daily in our day by day life. A clear example is when we consume food of any kind, each of these foods contains a reference amount of energy in kilocalories (kcal). These foods supply energy to the human body, this energy from food is used for different day actions, and much to maintain body temperature. When the human body is exposed to very low outside temperatures, the body is exposed to a considerable loss of energy in the form of heat transfer, so the person will begin to feel hungry so that the body needs calories from food to maintain body temperature at stable levels. Metabolism is essential in the human body, at the moment when the human being dies his temperature decreases because the metabolism stops working.

3 0
3 years ago
A closed system consisting of 10 lb of air undergoes a polytropic process from p1 = 75 lbf/in2, v1 = 4 ft3/lb to a final state w
Vitek1552 [10]

Answer:

The polytropic exponent (n) is 1.2

The amount of energy transfer by work is 552.45 Btu

Explanation:

P1V1^n = P2V2^n

P1 = 75 lbf/in^2 = 75 lbf/in^2 × 143.3 in^2/ft^2 = 10,747.5 lbf/ft^2

V1 = 4 ft^3/lb × 10 lb = 40 ft^3

P2 = 20 lbf/in^2 = 20 × 143.3 = 2866 lbf/ft^2

V2 = 12 ft^3/lb × 10 lb = 120 ft^3

(V2/V1)^n = P1/P2

(120/40)^n = 10747.5/2866

3^n = 3.75

ln 3^n = ln 3.75

n ln 3 = ln 3.75

n = ln 3.75/ln 3 = 1.2

W = (P2V2 - P1V1)/1 - n = (2866×120 - 10747.5×40)/1-1.2 = (343,920 - 429,900)/-0.2 = -85,980/-0.2 = 429,900 lbf.ft = 429,900/778.17 Btu = 552.45 Btu

4 0
3 years ago
The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the pla
Mrrafil [7]

Answer:

F'=708.53 N

Explanation:

We have,

The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,

F=kAv^2

k is constant

If, A = 190 Ft², v = 220 mph, F = 950 pounds

Let's find k first from above data. So,

k=\dfrac{F}{Av^2}\\\\k=\dfrac{950}{190\times 220^2}\\\\k=0.0001033

It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,

F'=0.0001033\times 190\times (190)^2\\\\F'=708.53\ \text{pounds}

So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.

3 0
3 years ago
Two identical billiard balls are rolling toward each other at the same speed. What will be true after they collide head–on? They
mylen [45]
<span> They will both stop rolling immediately after the collision.</span>
5 0
3 years ago
Read 2 more answers
A man does 1500 J of work to pull a box of 150 N. what is the displacement of the box?
Assoli18 [71]
  • Work done=1500J
  • Force=150N
  • Displacement =?

We know

\boxed{\sf Work\:Done=Force\times Displacement}

\\ \sf\longmapsto 1500=150\times Displacement

\\ \sf\longmapsto Displacement=\dfrac{1500}{150}

\\ \sf\longmapsto Displacement=10m

5 0
2 years ago
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