D.N(Newton) this is the S.I unit for force
Answer:
Reorder the steps so that step 4 appears before step 3
Explanation:
In a nuclear power plant, we have;
1) Nuclear reaction between the radio active species and the particles takes place to generate energy in the nucleus of atoms
2) The nuclear energy in the atom is converted into radiant energy, which is the energy found in light, and thermal (heat) energy
3) The produced radiant and thermal energy is released as heat and light
4) With the produced heat, steam is generated
5) The generated steam turns the steam turbines and produced mechanical energy
6) The produced mechanical energy is then converted into electrical energy in the electrical generator of the power plant
To correct Savion's error, Step 4) the light and heat should be released before step 3) the released heat can be used to generate steam, we therefore reorder the steps so that step 4 appears before step 3.
To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:
Mass of copper wire
Density 
Resistively of copper 
Resistance (R) = 0.390\Omega
Volume is defined as,
(1)
We know that,
(2)
Multiplying equation we have
Therefore the length of the wire is 1.68m
Answer: True.
Explanation:
A resistance force is also known as friction. And the efficiency of a machine is affected by friction.
A machine of lower efficiency has higher magnitude of friction than a machine of higher efficiency.
Therefore, To obtain the same resistance force, a greater force must be exerted in a machine of lower efficiency than in a machine of higher efficiency. This is true
Answer: FR=2.330kN
Explanation:
Write down x and y components.
Fx= FSin30°
Fy= FCos30°
Choose the forces acting up and right as positive.
∑(FR) =∑(Fx )
(FR) x= 5-Fsin30°= 5-0.5F
(FR) y= Fcos30°-4= 0.8660-F
Use Pythagoras theorem
F2R= √F2-11.93F+41
Differentiate both sides
2FRdFR/dF= 2F- 11.93
Set dFR/dF to 0
2F= 11.93
F= 5.964kN
Substitute value back into FR
FR= √F2(F square) - 11.93F + 41
FR=√(5.964)(5.964)-11.93(5.964)+41
FR= 2.330kN
The minimum force is 2.330kN
