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Lady bird [3.3K]
3 years ago
12

A solution containing potassium bromide is mixed with one containing lead acetate to form a solution that is 0.013 M in KBr and

0.0035 M in Pb(C2H3O2)2.Will a precipitate form in the mixed solution? If so, identify the precipitate.Express answer as a chemical formula.Please explained how you determined the answer.

Chemistry
1 answer:
galben [10]3 years ago
7 0

Answer:

No precipitate will form on mixing potassium bromide and lead acetate

Explanation:

Precipitation occurs when the ionic product of the ions exceeds the solubility product of the corresponding salt in the solution. If, this implies that the solution is over saturated and precipitation of salt will occur.Potassium bromide and lead acetate are strong electrolyte and thus completely dissociate in water.

The dissociation reaction is given as,Potassium bromide and lead acetate react to give lead bromide and potassium acetate.The concentration of lead ions is equal to the concentration of.The concentration of bromide ion is equal to the concentration of.Potassium acetate is soluble in aqueous solution. Lead bromide will precipitate out if the ionic product of lead ion and bromide ion exceeds the solubility product of .

The value of solubility product constant,, for is.The reaction quotient for is calculated as,Substitute the values.The value of the reaction quotient for is less than its solubility product, , therefore, precipitation of will not occur.

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Answer:

It should be D.

Explanation:

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3 years ago
A balloon occupies a volume of 2.00 l at 40.0oc. how much volume will it occupy at 30.0oc?
hodyreva [135]
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Where V is the volume and T is the temperature in Kelvin of the gas. We can use this for two situations as,
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T₂ = 30.0 ⁰C = 303 K

By applying the formula,
2.00 L / 313 K = V₂ / 303 K                   
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7 0
4 years ago
How many liters of air must react with 2500 mL of hexane in order for combustion to occur completely. The percentage of oxygen i
bagirrra123 [75]

Answer:

118750 ml

Explanation:

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From the equation of the reaction;

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2500 mL of C6H14 would react with x ml of O2

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2500 = x

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Since oxygen is 20% of air;

23750 = 20 / 100 * (Volume of air)

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