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4 years ago

Which of these is a mixture? a.water b.sugar c.carbon dioxide d.popcorn and salt

Chemistry

1 answer:

Dmitry_Shevchenko [17]4 years ago

7 0

Popcorn and salt as the mixtures are substances which are formed by mixing other substances

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The standard reduction potentials for the Ag+|Ag(s) and Zn2+| Zn(s) half-cell reactions are +0.799 V and -0.762 V, respectively.

mihalych1998 [28]

Answer: The potential of the given cell is 1.551 V

Explanation:

The given chemical cell follows:

$Zn(s)|Zn^{2+}(0.125M)||Ag^{+}(0.240M)|Ag(s)$

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(0.125M)+2e^-;E^o_{Zn^{2+}/Zn}=-0.762V$

Reduction half reaction: $Ag^{+}(0.240M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.799V$ ( × 2)

Net cell reaction: $Zn(s)+2Ag^{+}(0.240M)\rightarrow Zn^{2+}(0.125M)+2Ag(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.799-(-0.762)=1.561V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Zn^{2+}]}{[Ag^{+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = ? V

$E^o_{cell}$ = standard electrode potential of the cell = +1.561 V

n = number of electrons exchanged = 2

$[Zn^{2+}]=0.125M$

$[Ag^{+}]=0.240M$

Putting values in above equation, we get:

$E_{cell}=1.561-\frac{0.059}{2}\times \log(\frac{(0.125)}{(0.240)^2})$

$E_{cell}=1.551V$

Hence, the potential of the given cell is 1.551 V

6 0

4 years ago

Which of the following relations is correct for exothermic and endothermic reactions?

Salsk061 [2.6K]

Answer:

pa helpppp

Explanation:

pleseee need answerrrr

4 0

3 years ago

An object has a mass of 20 g and displaces a volume of 5 mL. What is the object's density?

lara [203]

Hey There!:

The density is the quotient between the mass of a material and the volume occupied by it, The density can be expressed for a substance or for a mixture of substances. For example, water density in ambient conditions is equal to 1.00 g/cm3, which means that in 1 cm³ or 1 mL, there are 1.0 g of water. Therefore:

D = m / V

D = 20 g / 5 mL

D = 4,0 g/mL

hope that helps!

5 0

3 years ago

A compound is composed of only C, H, and O. The combustion of a .519-g sample of the compound yields 1.24 g of CO_2 and .255 g o

Kay [80]

Answer:

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of compound = 0.519 g

Mass of CO₂ = 1.24 g

Mass of H₂O = 0.255 g

Empirical formula = ?

Solution:

%age of C,H,O

C = 1.24 g/0.519 × 12/44 ×100 = 65.5%

H = 0.255 g/0.519 × 2.016/18 ×100 = 5.6%

O = 100 - (65.5+5.6)

O = 28.9%

Number of gram atoms of H = 5.6 / 1.01 = 5.5

Number of gram atoms of O = 28.9 / 16 = 1.81

Number of gram atoms of C = 65.5 / 12 = 5.5

Atomic ratio:

C : H : O

5.5/1.81 : 5.5/1.81 : 1.81/1.81

3 : 3 : 1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

8 0

4 years ago

HURRY Give three examples of unbalanced forces in your everyday life.

Sonbull [250]

Answer:

Tug of War

An object sinking in water

Kicking a ball

7 0

2 years ago

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Which of these is a mixture? a.water b.sugar c.carbon dioxide d.popcorn and salt​

Which of these is a mixture? a.water b.sugar c.carbon dioxide d.popcorn and salt