How many moles are in 9.25 x 10^58 atoms of copper

Chemistry

1 answer:

olga2289 [7]4 years ago

6 0

Hey there!

There are 6.022 x 10²³ atoms of copper in one mole of copper.

So, divide 9.25 x 10⁵⁸ by 6.022 x 10²³.

(9.25 x 10⁵⁸) ÷ (6.022 x 10²³) = 1.54

There are 1.54 moles of iron in 9.25 x 10⁵⁸ atoms of copper.

Hope this helps!

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