How many moles are in 9.25 x 10^58 atoms of copper
1 answer:
Hey there!
There are 6.022 x 10²³ atoms of copper in one mole of copper.
So, divide 9.25 x 10⁵⁸ by 6.022 x 10²³.
(9.25 x 10⁵⁸) ÷ (6.022 x 10²³) = 1.54
There are 1.54 moles of iron in 9.25 x 10⁵⁸ atoms of copper.
Hope this helps!
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