How many moles are in 9.25 x 10^58 atoms of copper

1 answer:

6 0

Hey there!

There are 6.022 x 10²³ atoms of copper in one mole of copper.

So, divide 9.25 x 10⁵⁸ by 6.022 x 10²³.

(9.25 x 10⁵⁸) ÷ (6.022 x 10²³) = 1.54

There are 1.54 moles of iron in 9.25 x 10⁵⁸ atoms of copper.

Hope this helps!

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fomenos

<h2>ANSWER OF EACH PART ARE GIVEN BELOW</h2>

Explanation:

We know, each mole contains $N_A=$ $6.023 \times 10^{23}$ atoms.

It is given that mass of one oxygen atom is m= $2.66\times 10^{-23}\ g$ .

Therefore, mass of one mole of oxygen, $M=m\times N_A$ .

Putting value of n and $N_A$ ,

$M=2.66\times 10^{-23}\times 6.023\times 10^{23} \ gm\\M=16.0\ gm$

Given,

Mass of water in glass=0.050 kg = 50 gm.

From above part mass of one mole of oxygen atoms = 16.0 gm.

Therefore, number of mole of oxygen equivalent to 50 gm oxygen $=\dfrac{50}{16}=3.1 \ moles.$

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3 0

3 years ago

lesya [120]

Answer:

B.They all have their valence electrons in the same type of subshell

Explanation:

The electron configurations of elements in the same group (column) of the periodic table have them in the same type of subshell.
But the subshells may be of different shells. Thus , the energies of them need not be the same.
For example , The Alkalai Metals are found in the first column of the periodic table Group IA. This set of elements all have valence electrons in only the ' $s$ ' orbital and because they are in the first column they all have $s^{1}$ configuration. i.e,