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Llana [10]
2 years ago
11

What is Science?

Chemistry
2 answers:
Bas_tet [7]2 years ago
4 0
I agree Jesus is the answer
DENIUS [597]2 years ago
3 0

Answer:

jesus

Explanation:

Jesus is always the answer LOL

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When you heat a substance what happens to the molecules
tatyana61 [14]
I'm pretty sure they come closer, and on the small chance i'm wrong, they separate.<span />
6 0
2 years ago
Read 2 more answers
What is the name of the compound made from Sn 4+ and PO4 3-?
givi [52]

Answer:

Sn₃(PO₄)₄ - tin(IV) phosphate.

Explanation:

Hope it helps! :)

8 0
2 years ago
How to prepare super saturated solution of copper sulphate ? Explain the experiment
expeople1 [14]

Explanation:

Monitor the temperature of the water with the thermometer. Stop heating the water once it nears the boiling point of 100 degrees Celsius. Add copper(II) sulfate and stir until the heated solution is saturated. When the solution is saturated, copper(II) sulfate will not dissolve anymore

6 0
2 years ago
Use the following half-reactions to write three spontaneous reactions, calculate E°cell for each reaction, and rank the oxidizin
Ainat [17]

Answer:

See explaination

Explanation:

1)

we know that

half cell with higher reduction potential is cathode

so

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

anode :

Cr(s) ---> Cr+3 + 3e-

so

overall reaction is

3 N20 + 6H+ + 2 Cr ---> 3N2 + 3H20 + 2Cr+3

now

Eo cell = Eo cathode - Eo anode

so

EO cell = 1.77 + 0.74

Eo cell = 2.51 V

now

in this case

oxidizing agents are N20 and Cr+3

reducing agents are Cr and N2

higher the reduction potential , stronger the oxidizing agent

lower the reduction potential , stronger the reducing agent

so

oxidzing agents

N20 > Cr+3

reducing agents

Cr > N2

2)

cathode :

Au+ + e- --> Au

anode :

Cr ---> Cr+3 + 3e-

overall reaction

3Au+ + Cr ---> 3Au + Cr+3

Eo cell = 1.69 + 0.74

Eo cell = 2.43

now

oxidizing agents :

Au+ > Cr+3

reducing agents :

Cr > Au

3)

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

andoe :

Au ---> Au+ + e-

overall

2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20

Eo cell = 1.77 - 1.69

Eo cell = 0.08

oxidizing agents

N20 > Au+

reducing agents

Au > N2

8 0
3 years ago
N each reaction box, place the best reagent or reactant from the list below. reagents may be used more than once or not at all.
Ne4ueva [31]

Answer:

See explaination

Explanation:

See attachment for the drawing of the intermediate products b and c (both are neutral; omit byproducts).

7 0
3 years ago
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