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Llana [10]
2 years ago
11

What is Science?

Chemistry
2 answers:
Bas_tet [7]2 years ago
4 0
I agree Jesus is the answer
DENIUS [597]2 years ago
3 0

Answer:

jesus

Explanation:

Jesus is always the answer LOL

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1.3-3 Determine whether each of the following statements is true or false. If the statement is false, demonstrate this by proof
Inga [223]

Answer:

(a)False (b)False (c)False (d)False (e)False

Explanation:

a) Continuous time signal can also be digital. e.g continuous time square waveform (see first picture)

b) A discrete time signal can also be analog. e.g discrete time exponential function can take any value (see second picture)

c) When both energy and power of signal are infinite, it is neither power signal nor energy signal e.g ramp signals, e^{t}u(t) signal

d)A signal of infinite length can also have finite energy. e. g e^{t}u(t)

e)Step waveform u(t) is a power signal but also causal

3 0
3 years ago
Sensitivity analysis is concerned with how certain changes affect
Ilia_Sergeevich [38]
The answer here is letter C. The optimal solution. The optimal solution is the one that affects how certain things changes with sensitivity analysis. The optimal solution is a feasibility solution where the objective function of it is to reach the minimum and maximum value.
8 0
3 years ago
Given the balanced equation 2C4H10 + 13O2 → 8CO2 + 10H2O, how many moles of CO2 are produced when 14.9g of O2 are used?
Anna [14]

Answer: The number of moles of CO_2 produced are, 0.287 moles.

Explanation : Given,

Mass of O_2 = 14.9 g

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol

Now we have to calculate the moles of CO_2

The balanced chemical equation is:

2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the reaction, we conclude that

As, 13 mole of O_2 react to give 8 moles of CO_2

So, 0.466 mole of O_2 react to give \frac{8}{13}\times 0.466=0.287 mole of CO_2

Therefore, the number of moles of CO_2 produced are, 0.287 moles.

3 0
3 years ago
HELPPP!!! What is the volume of a 1.31 moles sample of gas if the pressure is 904 mmHg and the temperature is 37. degrees Celsiu
Tju [1.3M]

Answer:

27.99 dm³

Explanation:

Applying

PV = nRT................ Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

From the question, we were aksed to find V.

Therefore we make V the subject of the equation

V = nRT/P................ Equation 2

Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm

Constant: R = 0.082 atm.dm³/K.mol

Substitute these values into equation 2

V = (1.31×310×0.082)/(1.1897)

V = 27.99 dm³

4 0
3 years ago
7. A cyclist starting from rest accelerates at a rate of 6 m/s until she reaches 30 m/s. How long
Hunter-Best [27]

Answer:

Explanation:

The given values are:

a= 6m/s²

u= 0 m/s

v = 30 m/s

t= ?

The formula is :

a=\frac{v-u}{t}

thus,

t=\frac{v-u}{a}\\t=\frac{30-0}{6}\\t= 5 seconds

4 0
3 years ago
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