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ki77a [65]
3 years ago
14

Which statement about anabolism is true?

Chemistry
2 answers:
skelet666 [1.2K]3 years ago
8 0

Answer:

i would say B? Im sorry if im wrong

Explanation:

i think that because Catabolic reactions release energy, while anabolic reactions use up energy. Anabolism is the opposite of catabolism.

Anarel [89]3 years ago
3 0

Answer:

b

Explanation:

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How many gallons of gasoline that is 5% ethanol must be added to 2,000 gallons of gasoline with no ethanol to get a mixture that
Amanda [17]

Answer:

V_1= 3000 gal

Explanation:

We have 3 solutions:

  • Solution 1 (with ethanol)
  • Solution 2 (no ethanol)
  • Final solution

V_f=V_1 + V_2

and for the ethanol:

V_f*0.03=V_1*0.05 + V_2*0

V_f=V_1 \frac{5}{3}

Combining:

V_1 \frac{5}{3}=V_1 + V_2

V_1 \frac{2}{3}= V_2

V_1= \frac{3}{2} V_2

If V2=2000 gal:

V_1= \frac{3}{2} 2000 gal

V_1= 3000 gal

8 0
3 years ago
why do all of these elements- hydrogen, helium, lithium, and beryllium all have negative charges? explain
Dmitry_Shevchenko [17]
They all don’t, they also can have positive charges like LiOH (Lithium Hydroxide)
3 0
3 years ago
A 1.26 m aqueous solution of an ionic compound with the formula mx2 has a boiling point of 101.63 ∘c. part a calculate the van't
12345 [234]

<span>Answer is: Van't Hoff factor (i) for this solution is 1.051 .
Change in boiling point from pure solvent to solution: ΔT =i · Kb · b.
Kb - </span><span>molal boiling point elevation constant</span><span> is 0.512°C/m.
b -  molality, moles of solute per kilogram of solvent.
b = 1.26 m.
ΔT = 101.63°C - 100</span>°C = 1.63°C.

i = 1.63°C ÷ (0.512°C/m · 1.26 m).

i = 1.051.

5 0
3 years ago
Read 2 more answers
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
Which defines health?
NARA [144]
I mean this is pretty obvious it's D. life expectancy is sort of close but not really. B is close too but it's not it bc that's not what health is. you could be over weight and not be sick and it still isn't healthy. and C isn't close at all. hope this helps, have an amazing day :)
7 0
3 years ago
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