Question

Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I0. There will be a quantity (10 dB) involved in your calculations. When you enter your answer, leave off the unit dB.

Answer 1

Answer:

$I = I_o (10^{\frac{\beta}{10}})$

Explanation:

As we know that sound level is given as

$\beta = 10 Log (\frac{I}{I_o})$

so here we have

$\frac{\beta}{10} = Log(\frac{I}{I_o})$

now we can take anti log both sides

$10^{\frac{\beta}{10}} = \frac{I}{I_o}$

so we have

$I = I_o (10^{\frac{\beta}{10}})$

so above is the expression for the intensity of sound in terms of reference intensity and sound level