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loris [4]
3 years ago
8

How many moles ofO are present in 3.5 mol of Al2(SO4)3

Chemistry
1 answer:
ehidna [41]3 years ago
5 0

Answer:

Name of the compound is aluminum sulphate. chemical formula Al2(SO4)3

In that compound there are two aluminum atoms; three sulphur and 4*3=12 oxygen atoms.

2 oxygen atoms is equivalent to 1 mole oxygen.

so 12 oxygen is equivalent to 12÷2=6 mole oxygen.

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Discuss the different observations that you would record during an investigation into the energy transformations of a lamp that uses electrical energy.

4 0
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9. The prefix oct- means
dusya [7]

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2nd option

Explanation:

it means that there are 8 carbons

3 0
3 years ago
A sample of hydrogen gas at a pressure of 0.926 atm and a temperature of 29.5 C, occupies a volume of 457 mL. If the gas is allo
klio [65]

Answer:

V₂ = 946.72 mL

Explanation:

Given data;

Initial pressure = 0.926 atm

Initial volume = 457 mL

Temperature = constant = 29.5°C

Final pressure = 0.447 atm

Final volume = ?

Solution:

The given problem will be solved through the Boyle's law,

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

by putting values,

P₁V₁ = P₂V₂

0.926 atm × 457 mL = 0.447 atm × V₂

V₂ = 423.18 atm. mL/ 0.447 atm

V₂ = 946.72 mL

4 0
3 years ago
What mass of hydrogen is produced when 192 g of magnesium is reacted with hydrochloric acid?​
mariarad [96]

Answer:

Mg+2HCL-Magnesium Chloride +Hygrogen

>

Explanation:

N.O of moles=Mass\Molar Mass

192÷24=8

1:1

8×2=16

3 0
2 years ago
Read 2 more answers
If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature? (2005 K)
jolli1 [7]

Answer:

205K

Explanation:

The following were obtained from the question:

n = 4moles

P = 5.6atm

V = 12L

R = 0.082atm.L/Kmol

T =?

PV = nRT

T = PV/nR

T = (5.6 x 12)/ (4 x 0.082)

T = 205K

8 0
3 years ago
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