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Viefleur [7K]
3 years ago
9

Which of the following is NOT true regarding Rutherford's Gold Foil experiment?

Chemistry
1 answer:
erastova [34]3 years ago
8 0

Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.

Hope this info is useful.

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Devise a temperature scale, abbreviated g, for which the magnitude of the ideal gas constant is 1.00 j g–1 mol–1 .
melisa1 [442]

The value of ideal gas constant (R) in Joule is 8.314 Joule Kelvin^{-1}mol^{-1}. Now the given expression is 1.00 J. gg^{-1}.mole^{-1}. Where the g represent the temperature. Thus the abbreviated g must have the value 8.314 to satisfy the original value. Thus the temperature scale will be 1 kelvin = 8.314 g. Now 1 kelvin  = -272.15°C or in terms of abbreviation of g we can write -272.15 °C = 8.314g, or, 1°C  = (-) \frac{8.314}{272.15}=0.030g. Thus the temperature scale of the g scale is 1 kelvin (K) = 8.314g and 1°C = 0.030 g.  

7 0
4 years ago
Read 2 more answers
Calculate the amount, in moles, of each of the following. You may round atomic masses to one decimal place.
Vlada [557]

Answer:

The answer to your question is:

a) 0.023 mol of CdS

b) 0.12 mol of MoO3

c) 7.3 mol of AlPO4

Explanation:

a) CdS

MW = 112.4 + 32

      = 144 g

                                144g ------------------ 1 mol

                                  3.28g --------------  x

                                 x = (3.28 x 1) / 144

                                 x = 0.023 mol

b) MoO3

MW = 96 + 3(16) = 144 g

                              144g -------------------  1 mol

                               17.5g -----------------   x

                               x = (17.5 x 1) / 144

                               x = 0.12 mol

c) AlPO4

MW = 27 + 31 + 4(16)

MW = 122 g

                            122 g ------------------  1mol

                            890 g ------------------   x

                            x = (890 x 1) / 122

                            x = 7.3 mol of AlPO4

7 0
3 years ago
Hydrazine (N2H4) emits a large quantity of
azamat

Answer:

              1.75 moles of H₂O

Solution:

The Balance Chemical Equation is as follow,

                                   N₂H₄  +  O₂    →    N₂  +  2 H₂O

Step 1: Calculate the Limiting Reagent,

According to Balance equation,

             32.04 g (1 mol) N₂H₄ reacts with  =  32 g (1 mol) of O₂

So,

                   28 g of N₂H₄ will react with  =  X g of O₂

Solving for X,

                       X  =  (28 g × 32 g) ÷ 32.04 g

                       X  =  27.96 g of O₂

It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.

Step 2: Calculate moles of Water produced,

According to equation,

            32.04 g (1 mol) of N₂H₄ produces  =  2 moles of H₂O

So,

                        28 g of N₂H₄ will produce  =  X moles of H₂O

Solving for X,

                      X  =  (28 g × 2 mol) ÷ 32.04 g

                      X  =  1.75 moles of H₂O

5 0
4 years ago
The HF bond length is 92 pm, 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm). Suggest a reason for thi
Elza [17]

Due to electronegativity difference between H and F atom.

<h3>What is the reason for the difference ?</h3>
  • The bond length of HF is 92 pm. It is 16% shorter than the sum of the covalent radii of H (37 pm) and F (72 pm).
  • The shorter of the bond length is due to the difference in electronegativity between H and F atom. The electronegativity of F is 4.0, whereas the electronegativity of H is 2.1.
  • Greater the difference of electronegativity between the bonded atoms, shorter will be the bond length.
  • As  becomes smaller i.e. as we proceed from HF to HI, this effect becomes lessens and bond length will be more predictable.

Thus from the above conclusion we can say the difference in electronegativity between H and F atom this is the reason for shorter bond length of HF.

Learn more about bond length here :

brainly.com/question/13683866

#SPJ4

3 0
1 year ago
What do you mean by hydrocarbons???<br><br><br>Good night​
riadik2000 [5.3K]

Answer:

A hydrocarbon is any of a class of organic chemicals made up of only the elements carbon (C) and hydrogen (H). The carbon atoms join together to form the framework of the compound, and the hydrogen atoms attach to them in many different configurations

8 0
3 years ago
Read 2 more answers
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