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3 years ago

Which of the following is NOT true regarding Rutherford's Gold Foil experiment?

Chemistry

1 answer:

erastova [34]3 years ago

8 0

Answer:

The area around the nucleus must be of low mass.

Explanation:

Rutherford`s experiment showed that there are some positive charges in the center of the atoms, and because they are all together, they will give a great mass to the atom.

It was quite different from Thomson`s experiment, in which it was thought that the negative charges were mixed with the positive charges, around the atom (like a Pudding Model). In Rutherford`s experiment, because the direction of beta particles, it was the prediction of the positive nucleus.

Hope this info is useful.

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URGENTTTTT HELPPPP PLZZZ LAST TRYYY

algol13

Left Panel

A is an acid. Not the answer.

B is correct. That would be a base. But it is not an Arrhenius base. Keep reading.

C that is exactly what an Arrhenius base is.

D. No an acid of some sort would accept OH ions.

Right Panel

D is concentrated and it is also a weak base. Good cleaning fluid. Smells awful but it works.

8 0

3 years ago

Carboxyhemoglobin may be formed when a person inhales air that contains

elena-14-01-66 [18.8K]

Answer is none of the above

5 0

3 years ago

Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could

polet [3.4K]

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

= 4.56 g

So concentration = 4.56 g/dm3

8 0

3 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Anna11 [10]

Answer:

[COF₂] = 0.346M

Explanation:

For the reaction:

2COF₂(g) ⇌ CO₂(g) + CF₄(g)

Kc = 5.70 is defined as:

Kc = [CO₂] [CF₄] / [COF₂]² = 5.70 (1)

Equilibrium concentrations of each compound after addition of 2.00M COF₂ will be:

[COF₂] : 2.00M - 2x

[CO₂] : x

[CF₄] : x

Replacing in (1):

5.70 = [X] [X] / [2-2x]²

22.8 - 45.6x + 22.8x² = x²

0 = -21.8x² + 45.6x - 22.8

Solving for x:

X = 1.265 -False answer, will produce negative concentrations-

X = 0.827.

Replaing, molar concentration of COF₂ is:

[COF₂] : 2.00M - 2×0.827 = 0.346M

I hope it helps!

7 0

3 years ago

Will strontium bromide and potassium sulfate give a precipitate

antiseptic1488 [7]

Answer:- Yes, strontum bromide and potassium sulfate gives a precipitate of strontium sulfate.

Explanations:- As per the solubility rules, all compounds of alkali metals are soluble.

Sulfate of most of the alkaline earth metals like Ca, Ba and Sr are insoluble.

A double displacement reaction takes place when strontium bromide and potassium sulfate are mixed and a precipitate of strontium sulfate is formed:

$Sr(Br)_2(aq)+K_2SO_4(aq)\rightarrow 2KBr(aq)+SrSO_4(s)$

Note: (aq) stands for aqueous and (s) stands for solid and here it's precipitate.

8 0

3 years ago