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SVETLANKA909090 [29]

3 years ago

9

A bag contains 10 blue, 6 green, and 4 red marbles. you choose one marble. without putting it back, you choose a second marble.

what is the probability that you first choose a green marble and then a blue marble?

2 answers:

Alex777 [14]3 years ago

7 0

2/20 is a possibility

amid [387]3 years ago

6 0

Answer:

P(green then blue) = 3/19

Step-by-step explanation:

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Answer:

There are 8008 possible outcomes are there the first time he grabs 6 chocolates

Step-by-step explanation:

The order in which the chocolates are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many possible outcomes are there the first time he grabs 6 chocolates?

6 chocolates from a set of 16. So

$C_{16,6} = \frac{16!}{6!(16 - 6)!} = 8008$

There are 8008 possible outcomes are there the first time he grabs 6 chocolates

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