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SVETLANKA909090 [29]
3 years ago
9

A bag contains 10 blue, 6 green, and 4 red marbles. you choose one marble. without putting it back, you choose a second marble.

what is the probability that you first choose a green marble and then a blue marble?
Mathematics
2 answers:
Alex777 [14]3 years ago
7 0
2/20 is a possibility 
amid [387]3 years ago
6 0

Answer:

P(green then blue) = 3/19

Step-by-step explanation:

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What is the answer for number 8 and pls give step by step
Pie

Answer:

Trapezoid 1 (left side):

Base 1 = 2

Base 2 = 5

Trapezoid 2 (right side):

Base 1 = 6

Base 2 = 8

Step-by-step explanation:

<u>1st trapezoid:</u>

b_1 = x

b_2 = x + 3

h = 4

Hence, area (from formula) would be:

A=\frac{h}{2}(b_1+b_2)\\A=\frac{4}{2}(x+x+3)\\A=2(2x+3)\\A=4x+6

<u>2nd trapezoid:</u>

b_1 = 3x

b_2 = 4x

h = 2

Putting into formula, we get:

A=\frac{h}{2}(b_1+b_2)\\A=\frac{2}{2}(3x+4x)\\A=1(7x)\\A=7x

Let's equate both equations for area and find x first:

4x+6=7x\\6=7x-4x\\6=3x\\x=\frac{6}{3}\\x=2

We can plug in 2 into x and find length of each base of each trapezoid.

Trapezoid 1 (left side):

Base 1 = x = 2

Base 2 = x + 3 = 2 + 3 = 5

Trapezoid 2 (right side):

Base 1 = 3x = 3(2) = 6

Base 2 = 4x = 4(2) = 8

8 0
3 years ago
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