I would say D.) The ball bounces many times suggesting the energy is used up efficiently
A rolling friction jdisns
To solve this problem we will use the kinematic equations of descriptive motion of a projectile for which both the height reached and the distance traveled are defined. From this type of movement the lion reaches a height (H) of 3m and travels a horizontal distance (R) of 10 m. Mathematically the equations that describe this movement are given as,
Dividing the two equation we have that
Substituting values of H and R, we get
Substituting the value of \theta in equation we get,
Therefore the speed of the mountain lion just as it leaves the ground is 9.98m/s at an angle of 50.2°
Answer:
1.5 m
Explanation:
Using the law of conservation of energy
Gain in potential energy by the skateboarder= Loss in kinetic energy by the skateboarder
PE=KE where KE represent potential energy, PE represent potential energy
where m is mass of skateboarder and v is velocity of skateboarder
PE=mgh where m is the mass of skateboarder, g is acceleration due to gravity which in this case is taken as and h is the highest point reached by the skateboarder. Equating PE=KE we have
and since m are on both LHS and LHS, the cancel
} and making h the subject of the above formula
Substituting v with 5.4 m/s and g as we obtain
Rounded off, h=1.5 m