a) x = 
at t = 5s

b) v = 
= 
at t = 5 s
v = 
c) a = 
= 28 - 12t
at t = 5 s
a = 28 -12*5= 28-60= -32 m/
d) At maximum positive coordinate velocity = 0
So, 

At t = 4.66 s

e) At t = 4.66 s
f) At maximum positive velocity a = 0


At t = 2.33 s
V = 
g) t = 2.33 s
h) When particle is not moving v = 0
So 

At t = 4.66 s
a = 
i) At t = 0s, X =0m
t = 5s, X = 100m
So, Displacement = 100m
Velocity = 
Answer:

Explanation:
This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.
The initial velocity is in the x-direction, and there is no acceleration in the x-direction.
On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.
Applying the equations of kinematics in the x-direction gives

For the y-direction gives

Combining both equation yields the y_component of the final velocity

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

The equilibrant force of the two given forces is 14.14 N.
<h3 /><h3 /><h3>What is equilibrant force?</h3>
- This is a single force that balances other given forces.
The given parameters:
- First force, F₁ = 10 N
- Second force, F₂ = 10 N
- Angle between the forces, θ = 90⁰
The equilibrant force of the two given forces is calculated as follows;

Thus, the equilibrant force of the two given forces is 14.14 N.
Learn more about equilibrant force here: brainly.com/question/8045102
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