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VARVARA [1.3K]
3 years ago
13

How much kinetic energy does a 6kg cart have when moving at 4 m/s?

Physics
1 answer:
Arturiano [62]3 years ago
3 0

Given:

mass = 6 kg

velocity = 4 m/s

To find:

Kinetic energy of the cart = ?

Formula used:

Kinetic energy = \frac{1}{2} m v^{2}

Where m = mass of the cart

v = velocity with which the cart is moving

Solution:

Kinetic energy of the moving cart is given by,

Kinetic energy = \frac{1}{2} m v^{2}

Where m = mass of the cart

v = velocity with which the cart is moving

Kinetic energy =\frac{1}{2} \times 6 \times \ 4 \times 4

Kinetic energy = 48 Joule

Thus, the kinetic energy of the moving cart is 48 Joule.

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Calculate the wavelength of a photon having 3.26 x 10^-19 joules of energy
bekas [8.4K]
The energy of a photon is given by:
E=hf
where h is the Planck constant and f is the photon frequency.
We know the energy of the photon, E=3.26 \cdot 10^{-19} J, so we can rearrange the equation to calculate the frequency of the photon:
f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz

And now we can use the following relationship between frequency f, wavelength \lambda and speed of light c to find the wavelength of the photon:
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm
8 0
3 years ago
Vivian went on a bicycle trip through Germany with her family. One afternoon, she rode her bicycle along a long flat road at a c
natima [27]

d = distance traveled by her on her bicycle on a long flat road = 24 kilometer

t = time taken by her to travel distance "d" on her bicycle on a long flat road = 1.2 hours

v = average speed of vivian = ?

we know that average speed is given as

v = d/t

inserting the values in the above formula

v = 24 kilometer / 1.2 hour

v = 20 kilometer/hour


hence the correct choice is

C) 20 km/h



8 0
3 years ago
The ms = 0.5645 and mk=0.1113 for a 30 N box on level ground. What level force is needed to start the box moving
nevsk [136]

Answer:

16.935 N

Explanation:

In order to make the box start moving, the level force applied on the box (F) must be greater than the force of static friction that keeps the box at rest, which is equal to

F_f = \mu_s (mg)

where

\mu_s = 0.5645 is the coefficient of static friction

(mg) = 30 N is the weight of the box

Therefore, the condition for F must be:

F \geq F_f\\F \geq \mu_k (mg)=(0.5645)(30 N)=16.935 N

So, the applied force must be greater than this value.

3 0
3 years ago
During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.22 s, how high does it rise? The accel
BigorU [14]

Answer:

47.4 m

Explanation:

When an object is thrown upward, it rises up, it reaches its maximum height, and then it goes down. The time at which it reaches its maximum height is half the total time of flight.

In this case, the time of flight is 6.22 s, so the time the ball takes to reach the maximum height is

t=\frac{6.22}{2}=3.11 s

Now we consider only the downward motion of the ball: it is a free fall motion, so we can find the vertical displacement by using the suvat equation

s=ut+\frac{1}{2}gt^2

where

s is the vertical displacement

u = 0 is the initial velocity

t = 3.11 s is the time

g=9.8 m/s^2 is the acceleration of gravity (taking downward as positive direction)

Solving the  formula, we find

s=\frac{1}{2}(9.8)(3.11)^2=47.4 m

7 0
3 years ago
A vector has an x component of 24.0 units and the magnitude of the vector is 25 units. Find
GrogVix [38]

Answer:

Magnitude of y-component=7 units

Direction= angle of vector A with x-axis= 16.26^{o}

Explanation:

Explained solution is in the picture attached

4 0
3 years ago
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