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3 years ago

How much kinetic energy does a 6kg cart have when moving at 4 m/s?

Physics

1 answer:

Arturiano [62]3 years ago

3 0

Given:

mass = 6 kg

velocity = 4 m/s

To find:

Kinetic energy of the cart = ?

Formula used:

Kinetic energy = $\frac{1}{2} m v^{2}$

Where m = mass of the cart

v = velocity with which the cart is moving

Solution:

Kinetic energy of the moving cart is given by,

Kinetic energy = $\frac{1}{2} m v^{2}$

Where m = mass of the cart

v = velocity with which the cart is moving

Kinetic energy = $\frac{1}{2} \times 6 \times \ 4 \times 4$

Kinetic energy = 48 Joule

Thus, the kinetic energy of the moving cart is 48 Joule.

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The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece

Brilliant_brown [7]

Answer:

10.01 cm

Explanation:

Given that,

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.

The average propagation speed for sound in body tissue is 1540 m/s.

We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

$v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{1540\times 0.13\times 10^{-3}}{2}\\\\d= $$0.1001\ m$

d = 10.01 cm

So, the reflection will occur at 10.01 cm.

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2 years ago

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defon

Answer:

Explanation:

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2 years ago

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2 years ago

Determine the value of the current in the solenoid so that the magnetic field at the center of the loop is zero tesla. Justify y

sleet_krkn [62]

Answer:

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Explanation:

The formula for magnetic field at the center of a loop is given as

B = μ $_{o}$ I / 2R

where B is the magnetic field

R is the radius of the loop

I is the current

and μ $_{o}$ is the magnetic permeability of free space which is a constant 4π × $10^{-7}$ newtons/ampere²

If the magnetic field at the center of the loop is 0, then μ $_{o}$ I = 0

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3 years ago

A newly discovered particle, the SPARTYON, has a mass 945 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART

Gennadij [26K]

Answer:

$\nu =1166\times 10^{20}Hz$

Explanation:

We have given the rest mass of SPARTYON = 945 times of mass of electron

We know that mass of electron $=9.11\times 10^{-31}kg$

So mass of SPARTYON $=945\times 9.11\times 10^{-31}=8608.95\times 10^{-31}kg$

Speed of light $c=3\times 10^8m/sec$

According to Einstein equation energy is given by

$E=mc^2=8608.95\times 10^{-31}\times (3\times 10^{8})^2=77480.55\times 10^{-15}j$

Now according to planks's rule

Energy is given by

$E=h\nu$ , here h is plank's constant $h=6.6\times 10^{-34}$

So $77480.55\times 10^{-15}=6.6\times 10^{-34}\nu$

$\nu =1166\times 10^{20}Hz$

3 0

3 years ago