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fgiga [73]
3 years ago
5

You are standing outside with two speakers. The temperature is 0 degrees C. The two speakers are playing sound of the same frequ

ency: a pure sinusoidal sound of the same frequency at the same phase. The speakers are playing at different amplitudes. One speaker is 1.230 meters from you and one is 1.425 meters from you. You hear no sound. Which of the following is a possible frequency of the sound being played?
a. 993 Hz
b. 331 Hz
c. 4965 Hz
d. 1655 Hz
e. 662 Hz
Physics
1 answer:
never [62]3 years ago
4 0

Answer:

Explanation:

No sound is heard , that means there is destructive interference at the place where sound is heard .

Path difference of the source of sound = 1.425 m - 1.230 m

= 0.195 m

Let frequency of sound be n .

wave length = velocity of sound at 0°C / n

λ = 330 / n

for destructive interference ,

path difference = ( 2m+1) λ /2 , where λ is wave length of sound.

0.195 m = ( 2m+1) λ /2

0.195 m = ( 2m+1)330 / 2n

2n = 1692.3 (2m+1)

If m = 0

n = 846 . which is nearest to given frequency of 993 Hz

So 993 Hz is the answer.

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What hanging mass will stretch a 3.0-m-long, 0.32 mm - diameter steel wire by 1.3 mm ? The Young's modulus of steel is 20×10^10
raketka [301]

Answer:

0.71 kg

Explanation:

L = length of the steel wire = 3.0 m

d = diameter of steel wire = 0.32 mm = 0.32 x 10⁻³ m

Area of cross-section of the steel wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (0.32 x 10⁻³)²

A = 8.04 x 10⁻⁸ m²

ΔL = change in length of the wire = 1.3 mm = 1.3 x 10⁻³ m

Y = Young's modulus of steel = 20 x 10¹⁰ Nm⁻²

m = mass hanging

F = weight of the mass hanging

Young's modulus of steel is given as

Y = \frac{FL}{A\Delta L}

20\times 10^{10} = \frac{F(3)}{(8.04\times 10^{-8})(1.3\times 10^{-3})}

F = 6.968 N

Weight of the hanging mass is given as

F = mg

6.968 = m (9.8)

m = 0.71 kg

7 0
4 years ago
Sound waves travel fastest through a A) gas. B) liquid. C) solid. D) vacuum.
earnstyle [38]

Sound waves travel faster through <em>solids</em> than they do through gases or liquids.  <em>(C)  </em>They don't travel through vacuum at all.

Example:

Speed of sound in normal air . . . around 340 m/s

Speed of sound in water . . . around 1,480 m/s

Speed of sound in iron . . . around 5,120 m/s

3 0
4 years ago
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An action force is 40 N to the right. The reaction force must be: A. 20 N left B. 40 N left C. 20 N right D. 40 N right
Sergeeva-Olga [200]

Answer:

The answer to your question is letter B.

Explanation:

To answer this question, we must remember the third law of motion of Newton that states that For every action, there is an equal and opposite reaction.

Then, if the action force is 40 N to the right, the reaction force must be 40 N to the left.

8 0
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Why are some of the rocks on the moon older than the oldest known rocks on Earth?
Vadim26 [7]
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6 0
3 years ago
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If a woman needs an amplification of 1.0 ✕ 105 times the threshold intensity to enable her to hear at all frequencies, what is h
Damm [24]

Answer:

50 dB.

Explanation:

given,

Amplification needed by the woman,I= 1 x 10⁵ I₀

where as I₀ is the threshold frequency

overall hearing loss of the woman= ?

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The overall hearing loss of woman is equal to 50 dB.

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