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uranmaximum [27]
3 years ago
12

Armand is monitoring a large sealed tank by way of a sensor that records the liquid level over time on a graph. He looks at the

graph and claims that the sensor indicates there are waves in the liquid in the tank.
In the space provided, answer each of the following.

Part A: Explain how Armand knows that there is a wave in the tank.
Part B: Find the amplitude, in centimeters (cm), and frequency, in number of waves every second/cycle per second (Hz), of the wave.
Physics
2 answers:
Brums [2.3K]3 years ago
5 0

Answer:

A.) armand probably looked at the graph that the liquid sensor sends information too

Explanation:

timofeeve [1]3 years ago
4 0

Answer:

i need ppoints

Explanation:

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Good evening everyone, State the law of conservation of energy .Thank u​
disa [49]

<em>Energy</em><em> </em><em>can</em><em> </em><em>neither </em><em>be</em><em> </em><em>created </em><em>nor</em><em> </em><em>be</em><em> </em><em>destroyed</em><em> </em><em>but</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>converted</em><em> </em><em>from</em><em> </em><em>one</em><em> </em><em>form</em><em> </em><em>to</em><em> </em><em>another </em><em>.</em>

3 0
3 years ago
Read 2 more answers
Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if
il63 [147K]

Answer:

That insane it might be true because  a planet sometimes quoted to be an Earth 2.0 or Earth's Cousin based on its characteristics; also known by its Kepler Object of Interest designation KOI-7016.01) is an exoplanet orbiting the Sun-like star Kepler-452 about 1,402 light-years (430 pc) from Earth in the constellation Cygnus.

Explanation:

7 0
3 years ago
A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if
Dmitrij [34]

To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

F_p = 6*10^{22}N

F_p = \frac{GMm}{R^2}

F_p = 9*10^{22}N

Distance between planet and star

r = \frac{R}{2}

Gravitational force is

F = \frac{GMm}{r^2}

Applying the new distance,

F = \frac{GMm}{(\frac{R}{2})^2}

F =  4\frac{GMm}{R^2}

Replacing with the previous force,

F = 4F_p

Replacing our values

F= 4(9*10^{22}N)

F = 36*10^{22}N

Therefore the magnitude of the force on the star due to the planet is  36*10^{22}N

5 0
3 years ago
I will Give Brainliest To whoever actually answers A 500 kg satellite experiences a gravitational force of 3000 N, while moving
snow_lady [41]

Answer:

9.7\times 10^{-4}\ rad/s

Explanation:

Given:

m=500 kg\\F=3000 N

Radius of earth , R=6371 \times 10^3\ m\\Angular speed =\omega\\We\  know\  that\ \\F= m\times \omega^{2} \times R\\\omega^{2}=\frac{F}{m*R} \\\\=\frac{3000}{500*6371 \times 10^3\ m}

=\frac{6}{6371 \times 10^3\ m}

=9.7\times 10^{-4}\ rad/s

7 0
4 years ago
You drop a ball from a height of 32 meters how much time passes before the ball hits the ground
tankabanditka [31]

Answer:

31 seconds

Explanation:

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5 0
3 years ago
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