Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let 
= <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z = 
~ N(0,1)
where, 
= population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P( > 259 cm)
P( > 259 cm) = P( > 
) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
240(3/5) = 144
240(2/5) = 96
144-96 = 48
48 boxes must be added
Answer:
C. 8a - 36
Step-by-step explanation:
a + 3a - 4(9-a)
a + 3a - 36 + 4a
8a - 36
Answer:
The value of a₁₀ is -1352
Step-by-step explanation:
a₂ = -8
a₅ = -512
Now,
a₂ = -8 can be written as
a + d = -8 ...(1) and
a₅ = -512 can be written as
a + 4d = -512 ...(2)
Now, from equation (2) we get,
a + 4d = - 512
a + d + 3d = - 512
(-8) + 3d = - 512 (.°. <u>a + d = </u><u>-8</u><u>)</u>
3d = - 512 + 8
3d = - 504
d = - 504 ÷ 3
d = - 168
Now, for the value of a put the value of d = -168 in equation (1)
a + d = -8
a + (-168) = -8
a - 168 = -8
a = 168 - 8
a = 160
Now, For a₁₀
a₁₀ = a + 9d
a₁₀ = 160 + 9(-168)
a₁₀ = 160 - 1512
a₁₀ = -1352
Thus, The value of a₁₀ is -1352
<u>-TheUnknownScientist</u>
Answer:
a: 130
b: 130
c: 50
Step-by-step explanation:
a straight line has an angle of 180, so those two angles are going to add up to 180. and opposite angles are equivalent
