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coldgirl [10]
3 years ago
5

What graph represents the function f(x) = 8 1/3^x?

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

B (second graph from left)

Step-by-step explanation:

The function when x=0 will be 1 since any number to the zero exponent is 1. This means only B and D are options.

Because of the fraction, the values will be smaller and have a gentler slope. B is the solution.

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A stapes bone has a mass of about 4.27mg.round this number to the nearest hundredth of a milligram ,the nearest of a tenth of a
hammer [34]

round to the nearest

hundredth of milligram :  4.27

tenth of milligram: 4.3

milligram : 4

8 0
3 years ago
Algebra 2A Help !<br><br> Tadakimasu ~
Ludmilka [50]
Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)

first factor into (x-r1)(x-r2)... form

p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)

multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2 

so

p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real

baseically

(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the  root 1 and has multiplity 1

7 0
3 years ago
A man who is 2 meters tall stands on level ground. He is 32 meters from the base of a tree. The angle of elevation of the top of
podryga [215]

Answer:

h = 16.92 m

Step-by-step explanation:

If you mean to man horizontal line of sight  then the height of the tree is:

h = 2m + x

x is one right side and second is distance from the base of a tree 32m.

Tangence in this right triangle is:

tan 25° = x / 32 => x = 32 · tan 25° = 32 · 0.4663 = 14.92m

h = 2 + 14.92 = 16.92m

God with you!!!

6 0
3 years ago
Read 2 more answers
How do you solve this equation 5/2c = 8 1/3
OLga [1]

Answer:

all work is shown and pictured

8 0
3 years ago
How do you determine where f(x)=cos^(-1)(lnx) is continuous?
olga nikolaevna [1]
\ln x is continuous over its domain, all real x>0.

Meanwhile, \cos^{-1}y is defined for real -1\le y\le1.

If y=\ln x, then we have -1\le \ln x\le1\implies \dfrac1e\le x\le e as the domain of \cos^{-1}(\ln x).

We know that if f and g are continuous functions, then so is the composite function f\circ g.

Both \cos^{-1}y and \ln x are continuous on their domains (excluding the endpoints in the case of \cos^{-1}y), which means \cos^{-1}(\ln x) is continuous over \dfrac1e.
7 0
3 years ago
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