Question

. What is the maximum constant speed with which a car can round a circular turn of radius 80.0 m ona flat road if the coefficient of static friction between tires and road isμs= 0.55

Answer 1

Answer:

Maximum constant speed with which a car can round is 20.76 m/s.

Explanation:

We know, for car to be move on flat road without slipping its  centripetal force should not exceed static friction.

Therefore, maximum value of friction must be equal to centripetal force.

Therefore, $\dfrac{mv^2}{r}=\mu_smg$

Now, putting all given values and $g = 9.8 \ m/s^2$.

We get , $\dfrac{v^2}{80}=0.55\times 9.8\\\\v^2=0.55 \times 9.8\times 80\\v=20.76\ m/s.$

Hence, this is the required solution.