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3 years ago

Use evidence to explain why glass refracted more light than air or water

Physics

1 answer:

agasfer [191]3 years ago

4 0

Explanation:

The refraction is the change in the direction of light while travelling from the one medium to another due to having different speeds in different mediums.

To determine how much light gets refracted, it depends on the density of substance and the wavelength and the angle at which light enters the substance.

Light travels more slowly in denser medium than the rarer medium. The refractive index of glass is more than water or air. Light gets refracted more in this. When the light travels from rarer to denser then the light will get bend towards the normal. When the light travels from denser to rarer then the light will get bend away from the normal.

Glass is more denser than air or water. Water is more denser than the air. When light travels from air to glass then the light gets bends towards the normal. When the light travels from glass to the air then light gets bends away from the normal.

Therefore, the light gets refracted more in the glass than air to water.

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Visible electrical discharge from a storm cloud is called?

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3 years ago

A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the

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Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

$a_c =w^2r = \frac{v^2}{r}$

in this case we know the speed of the runner

$v =8.00\ m/s$

The radius "r" will be the distance from the runner to the center of the track

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3 years ago

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3 years ago

The experimentation step of scientific inquiry involves _______. A. Analyzing data b. Drawing a conclusion c. Choosing variables

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Answer:

C- Choosing variables and controls

Explanation:

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2 years ago

In a certain region of space, the electric potential is V(x,y,z)=Axy-Bx^2+Cy , where A,B , and C are positive constants.a) Calcu

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Answer:

a) Eₓ = - A y + 2B x , b) Ey = -Ax –C , c) Ez = 0 , d) The correct answer is 3

Explanation:

The electric field and the electric power are related

E = - dV / ds

a) Let's find the electric field on the x axis

Eₓ = - dV / dx

dV / dx = A y - B 2x

Eₓ = - A y + 2B x

b) calculate the electric field on the y-axis

Ey = - dV / dy

dV / dy = A x + C

Ey = -Ax –C

c) the electric field on the z axis

dv / dz = 0

Ez = 0

.d) at which point the electric field is zero

Since the electric field is a vector quantity all components must be zero

X axis

0 = = - A y + 2B x

y = 2B / A x

Axis y

0 = -Ax –C

.x = -C / A

We substitute this value in the previous equation

.y = 2B / A (-C / A)

.y = 2 B C / A2

The correct answer is 3

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4 years ago