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Airida [17]
3 years ago
9

The current interest in continental drift was started with the notion of sea- floor spreading, which was propounded by Hess and

Dietz in the ________.A) 1700s B) 1850s C) 1990s D) 1890s E) 1960s
Physics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

idk

Explanation:

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If ball 4 has a mass of 2 kg and it is 5m high, what will be its gravitational potential energy? (g=10 N/kg) *
Nastasia [14]

Explanation:

Gravitational potential energy

= mgh

= (2kg)(10N/kg)(5m)

= 100J.

3 0
3 years ago
Read 2 more answers
A computer disk drive is turned on starting from rest and has a constant angular acceleration. If it took 0.750 seconds for the
Irina-Kira [14]

Answer:

a) Θ = ω₀*t + ½αt² To complete first revolution 2π rads = 0*t + ½αt² and to complete the first and second combined 4π rads = 0*t + ½α(t+0.810s)² Divide second by first: 2 = (t + 0.810s)² / t² This is quadratic in t and has roots at t = -0.336 s ← ignore and t = 1.96 s ◄ b) Use either equation from above: 2π rads = 0*t + ½α(1.96s)² α = 3.27 rad/s² ◄ Hope this helps!

Explanation:

6 0
3 years ago
Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
Marysya12 [62]

Answer:

<h2>The answer is 1376 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 8 × 10 × 17.2

We have the final answer as

<h3>1376 J</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
How do you calculate relative velocity?
nekit [7.7K]

Answer:

<h3>Vab=Va-Vb</h3><h3>Vab=Vb-Va</h3><h3>Explanation:</h3>

Vab is velocity of a relative to b

Vba is velocity of b relative to a

4 0
4 years ago
If the particle has mass m, how fast must it be moving away from the Sun's center of mass to escape the gravitational influence
IgorLugansk [536]

Answer:

Explanation:

M = 1.989 x 10^30 kg

R = 6.96 x 10^8 m

G = 6.67 x 10^-11 Nm²/kg²

Let the velocity is v.

v=\sqrt{\frac{2GM}{R}}

v=\sqrt{\frac{2\times 6.67\times 10^{-11}\times 1.989\times 10^{30}}{6.96\times 10^{8}}}

v = 6.17 x 10^5 m/s

3 0
3 years ago
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