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Anika [276]
3 years ago
14

An astronaut is out in space with an extremely precise timing device measuring the speed of various fast‑moving objects. A laser

gun is mounted on a spaceship and aimed backward. As the spaceship flies away from the astronaut at a speed of 200 million m/s, the laser shines a beam of light toward him. Determine the speed that would be measured in each of the cases listed. The speed of the laser light as measured in the astronaut's reference frame. The speed of the laser light measured in the spaceship's reference frame. The speed of the laser gun as measured in the astronaut's reference frame. The speed of the laser gun measured in the spaceship's reference frame.
Physics
1 answer:
Leviafan [203]3 years ago
5 0

Answer and Explanation:

with reference to Einstein's theory of special relativity, the speed of an electromagnetic radiation, here, laser will not change in any inertial frame or remains same irrespective of any change in inertial frame.

Therefore, the speed of light measured in both the cases, i.e., in astronaut's reference frame and spaceship's reference frame will be equal to the speed of light in vacuum, i.e., 3\times 10^{8} m/s.

The laser gun's speed in astronaut's reference frame is the same as the speed of the spaceship as it mounted on it, i.e., the speed of the laser gun is 200 million m/s.

The laser gun's speed measured in spaceship's reference frame will be zero, as it is mounted on the spaceship and is stationary in the spaceship's reference frame.

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A basketball player jumps straight up with a speed of 14 m/s. How high did the player jump?
alexira [117]

Answer:

<em>The basketball player jumped 10 m high.</em>

Explanation:

<u>Vertical Launch Upwards </u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

\displaystyle h_m=\frac{v_o^2}{2g}

The basketball player jumps up with a speed of vo=14 m/s. The maximum height is:

\displaystyle h_m=\frac{14^2}{2*9.8}

\displaystyle h_m=\frac{196}{19.6}=10

The basketball player jumped 10 m high.

7 0
3 years ago
a sample of ideal gas is originally at 40 degrees celsius. what is the final temperature of the gas if the volume is doubled and
Assoli18 [71]

Answer:

313 K or 40 degree celsius.

Explanation:

Initial , V_{i}=V_{0}

P_{i}=P_{0}

T_{i} =40+273=313K

Now, final

P_{f} =\frac{1}{2}P_{0}

V_{f} =2V_{0}

Combined  the ideal gas law

\frac{P_{i}V_{i}}{T_{i}}=\frac{P_{f}V_{f}}{T_{f}} \\\frac{P_{0}V_{0}}{T_{0}}=\frac{1}{2} \frac{P_{0}2V_{0}}{T_{f}} \\T_{f}=T_{0}\\T_{f}=313K

Therefore, the final temperature of ideal gas is 313 K.

4 0
4 years ago
A diffraction grating with 140 slits per centimeter is used to measure the wavelengths emitted by hydrogen gas. At what angles i
Degger [83]

Answer:

0.003181 radians

0.003005 radians

Explanation:

Number of slits = 140 /cm

λ = Wavelength = 434 nm = 434×10⁻⁹ m

m = 3 Third order spectrum

Space between slits

d=\frac{0.01}{140} =7.14\times 10^{-5}\ m

Now,

dsin\theta = m\lambda\\\Rightarrow \theta=sin^{-1}\left(\frac{m\lambda}{d}\right)\\\Rightarrow \theta=sin^{-1}\left(\frac{3\times 434\times 10^{-9}}{7.14\times 10^{-5}}\right)\\\Rightarrow \theta=sin^{-1}0.018228\\\Rightarrow \theta=0.01823^{\circ}=0.01823\times \frac{\pi}{180}=0.003181 radians

0.003181 radians

When λ = 410 nm = 410×10⁻⁹ m

dsin\theta = m\lambda\\\Rightarrow \theta=sin^{-1}\left(\frac{m\lambda}{d}\right)\\\Rightarrow \theta=sin^{-1}\left(\frac{3\times 410\times 10^{-9}}{7.14\times 10^{-5}}\right)\\\Rightarrow \theta=sin^{-1}0.01722\\\Rightarrow \theta=0.01722^{\circ}=0.01722\times \frac{\pi}{180}=0.003005 radians

0.003005 radians

5 0
4 years ago
Two iron weights, one twice the mass of the other, are dropped from the top of a building. Compared with the lighter weight, the
Whitepunk [10]
The twice as heavy weight will hit the ground with more force, or impact.
4 0
3 years ago
Read 2 more answers
) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th
Mademuasel [1]

Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

    m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w

Now, we will substitute 0 for both z_{1} and z_{2}, 0 for w, 334.9 kJ/kg for h_{1}, 2726.5 kJ/kg for h_{2}, 5 m/s for V_{1} and 220 m/s for V_{2}.

Putting the given values into the above formula as follows.

     m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w  

     1 \times [334.9 \times 10^{3} J/kg + \frac{(5 m/s)^{2}}{2} + 0] + q = 1 \times [2726.5 \times 10^{3} + \frac{(220 m/s)^{2}}{2} + 0] + 0

                q = 6597.711 kJ

Thus, we can conclude that heat transferred through the coil per unit mass of water is 6597.711 kJ.

6 0
4 years ago
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