1.806*10^24 atoms of carbon is how many moles of carbon

I need to right a journal entry for school but i don't know what to put Write a journal entry from the perspective of a particle

polet [3.4K]

Answer:

here you go

Explanation:

someone help me on this but i still got a hundred

5 0

2 years ago

What is the molarity of a NaOH solution if 28.2 mL of a 0.355 M H2SO4 solution is required to neutralize a 25.0-mL sample of the

Anni [7]

Answer:

A) 0.801

Explanation:

The reaction that takes place is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

First we calculate the H₂SO₄ moles that reacted:

0.355 M * 28.2 mL = 10.011 mmol H₂SO₄

Now we convert H₂SO₄ moles to NaOH moles:

10.011 mmol H₂SO₄ * $\frac{2mmolNaOH}{1mmolH_2SO_4}$ = 20.022 mmol NaOH

Finally we calculate the molarity of the NaOH solution:

20.022 mmol NaOH / 25.0 mL = 0.801 M

So the answer is option A.

3 0

3 years ago

The activation energy of an uncatalyzed reaction is 70 kJ/mol. When a catalyst is added, the activation energy (at 20 °C) is 42

denis23 [38]

Answer:

T = 215.33 °C

Explanation:

The activation energy is given by the Arrhenius equation:

$k = Ae^{\frac{-Ea}{RT}}$

Where:

k: is the rate constant

A: is the frequency factor

Ea: is the activation energy

R: is the gas constant = 8.314 J/(K*mol)

T: is the temperature

We have for the uncatalyzed reaction:

Ea₁ = 70 kJ/mol

And for the catalyzed reaction:

Ea₂ = 42 kJ/mol

T₂ = 20 °C = 293 K

The frequency factor A is constant and the initial concentrations are the same.

Since the rate of the uncatalyzed reaction (k₁) is equal to the rate of the catalyzed reaction (k₂), we have:

$k_{1} = k_{2}$

$Ae^{\frac{-Ea_{1}}{RT_{1}}} = Ae^{\frac{-Ea_{2}}{RT_{2}}}$ (1)

By solving equation (1) for T₁ we have:

$T_{1} = \frac{T_{2}*Ea_{1}}{Ea_{2}} = \frac{293 K*70 kJ/mol}{42 kJ/mol} = 488. 33 K = 215.33 ^\circ C$

Therefore, we need to heat the solution at 215.33 °C so that the rate of the uncatalyzed reaction is equal to the rate of the catalyzed reaction.

I hope it helps you!

4 0

4 years ago

How many moles are in 2.04 × 1024 molecules of h2o?

EleoNora [17]

Answer:

3.4moles

Explanation:

Given parameters:

Number of molecules = 2.04 x 10²⁴

Unknown: Number of moles

Solution

We use the concept of mole to solve this kind of problem.

A mole is the amount of substance that contains Avogadro's number of particle i.e 6.02 x 10²³ molecules

Solving

For elementary particles:

Number of moles = $\frac{number of particles}{6.02 x 10^{23} }$ ¹ molecules

Number of moles = $\frac{2.04 x 10^{24} }{6.02 x ^{23} }$

Number of moles of H₂O = 0.34 x 10¹ = 3.4moles

5 0

4 years ago

Given the reaction:CO2 + 6 H2O==> C6H12O6 + 6 O2

kari74 [83]

For every 1 mole of C6H12O6, you need 6 moles of water. Multiply the 2.5 moles you are trying to make by the 6 of water you need, and 4) 15 is your answer.

5 0

3 years ago

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