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Pepsi [2]
3 years ago
10

The density of helium in a 2.00 L tank at 1.0 atm and 23 degrees Celsius is?

Chemistry
1 answer:
andrezito [222]3 years ago
5 0

The output density is given as kg/m 3, lb/ft 3, lb/gal(US liq) and sl/ft 3. Specific weight is given as N/m 3 and lb f / ft 3.

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Brainliest to whoever gets it correct.
lakkis [162]

Answer:

replacement

Explanation:

here is the ans

7 0
3 years ago
Read 2 more answers
Cuando el oxígeno reacciona con el calcio produce un sólido blanco muy utilizado en la preparación de cementos. ¿Cuál de las sig
8_murik_8 [283]

Answer:

2Ca + O₂ → 2CaO

Explanation:

Cuando el Calcio (Ca) reacciona con oxígeno (O₂) se produce cal (CaO). La cal es un sólido inodoro de color blanco a grisáceo. La cal es un óxido que se encuentra presente en el cemento y su cuantificación permite determinar la calidad y el tipo de cemento a utilizar.

La reacción que describe el proceso anterior es:

Ca + O₂ → CaO

Para balancear los oxígenos, se deben poner 2 CaO como producto:

Ca + O₂ → 2CaO

Para balancear los calcios, se pone como coeficiente del Ca un 2:

<h3>2Ca + O₂ → 2CaO</h3><h3 />

Esta última es la reacción que describe el proceso anterior

6 0
3 years ago
Is ketchup a heterogeneous or homogeneous mixture? Explain your reasoning.
Norma-Jean [14]
Homogeneous because everything is mixed together evenly.
5 0
3 years ago
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All organisms on Earth have the information necessary for building them coded in their genes, and each gene is a part of the org
konstantin123 [22]

Answer:

C

Explanation:

7 0
3 years ago
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Hclo is a weak acid (ka=4.0x10^-8) and so the salt naclo acts as a weak base. what is the ph of a solution that is 0.037 m in na
ankoles [38]

<u>Given:</u>

Concentration of NaClO = 0.037 M

ka (HClO) = 4.0*10⁻⁸

<u>To determine:</u>

The pH of the NaClO solution

<u>Explanation:</u>

The hydrolysis of the weak base can be represented by the ICE table shown below-

                ClO-      +     H2O    ↔    HClO    +       OH-

Initial        0.037M                              0                    0

Change         -x                                 +x                  +x

Equilibrium  (0.037-x)                        x                     x

kb  = kw/ka =  [HClO][OH-]/[ClO-]

10⁻¹⁴/4*10⁻⁸ = x²/(0.037-x)

x = [OH-] = 9.62*10⁻⁵

p[OH-] = -log[OH-] = -log [9.62*10⁻⁵] = 4.02

pH = 14-p[OH-] = 14 - 4.02 = 9.98

Ans: pH of the solution is 9.98


7 0
3 years ago
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