How many grams of ammonia (NH3) are present in 5.0L of a 0.050M Solution?
2 answers:
Answer:
B. 4.3 g
Explanation:
m = 5.0L x 0.050 mol/L x 17.031 g/mol = 4.26g ~ 4.3g
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Answer:
B
Explanation:
NH3 in a liter is 17 x 0.05 = 0.85g
In 5L = 0.85 x 5 = 4.25 = 4.3g
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