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Alja [10]
3 years ago
6

Write 2/3 as a decimal.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

0.67

Step-by-step explanation:

2/3 = 0.6666

0.6666 rounded to the nearest hundredth = 0.67

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What number multiplied by itself 3 times equals 10
Vesna [10]

Answer:

2.1544

Step-by-step explanation:

\sqrt[3]{10} = 2.1544

check: 2.1544^3

7 0
2 years ago
In 1992, there were 120 students in the freshmen class. in 2005, there were 224. find the rate of change from 1992 to 2005.
kolezko [41]

b) 8

they were asking you about the rate of increase in students per year

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7 0
3 years ago
If a mechanic uses his credit card to pay for a compressor that costs $477.95 and does not pay on it until the second month, wha
Rina8888 [55]

Answer:

A. $7.17

Step-by-step explanation:

We have been given that a mechanic uses his credit card to pay for a compressor that costs $477.95 and does not pay on it until the second month.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nT} where,

A = Final amount after T years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Periods of compounding,

T = Time in years.

Let us multiply our given rate by 12 to get APR and convert it in decimal form.

APR=12\times 1.5\%

APR=18\%

18\%=\frac{18}{100}=0.18

Since 1 year equals 12 months, so 1 month will be 1/12 year.  

Upon substituting our given values in above formula we will get,

A=477.95(1+\frac{0.18}{12})^{12\times\frac{1}{12}}

A=477.95(1+0.015)^{1}

A=477.95(1.015)

A=485.11925

Now let us subtract principal amount from the final amount to get the monthly interest charge at the end of 1st month.

\text{The monthly interest charge be at the end of the first month}=485.11925-477.95

\text{The monthly interest charge be at the end of the first month}=7.16925\approx 7.17

Therefore, the monthly interest charge be at the end of the first month will be $7.17 and option A is the correct choice.

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Step-by-step explanation:

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What is the dashed green part of the figure below?
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