The sum of 3 consecutive integers is 309. Determine the middle integer.
2 answers:
Divide 309 by 3:
309 / 3 = 103
for the lower number subtract 1: 103 -1 = 102
for the higher number add 1: 103+1 = 104
The 3 numbers are 102, 103, 104
The middle number is 103.
The answer is C.
Hi WindowTrash14,
Solution:
To get the middle interger you need to divided the total by the 3 intergers:
309 / 3 = 103
103 x 3 = 309
Answer:
c) 103
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