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Artist 52 [7]
3 years ago
5

Which of the following choices has the ecological levels listed from largest to smallest?

Chemistry
1 answer:
wariber [46]3 years ago
3 0

Answer:

the answer is something  

Explanation:

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In which of the following is light energy converted to electrical energy
AleksandrR [38]
The answer is c.solar cell
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4 years ago
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* The cost of table salt and table sugar is Rs 15 per kg.
Vilka [71]

Cost per mole

Table salt : Rs 0.878

Table sugar : Rs 23.63

<h3>Further explanation</h3>

Given

Cost table salt (NaCl) = 15/kg

Cost table sugar(sucrose-C12H22O11) = 69/kg

Required

cost per mole

Solution

mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

\tt mol=\dfrac{1000~g}{58.5}=17.09~mol=Rs~15\rightarrow 1~mol=Rs~0.878

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

\tt mol=\dfrac{1000}{342}=2.92~mol=Rs~69\rightarrow 1~mol=Rs~23.63

6 0
3 years ago
What are the Common compounds of niobium in which it is found
blagie [28]

Explanation:

Common Compounds of Niobium Nb

[Nb+3, Nb+5]

Compound NameFormulaMolar Mass

Niobium(III) OxideNb2O3233.811

Niobium(III) SulfateNb2(SO4)3474.0006

Niobium(V) PhosphateNb3(PO4)5753.576

Niobium(V) BromideNbBr5492.4264

Niobium(V) PentoxideNb2O5265.8098

Niobium OxychlorideNbOCl3215.2648

Niobium(V) IodideNbI5727.4287

Niobium(V) PentachlorideNbCl5270.1714

Niobium(V) ThiocyanateNb(SCN)5383.3184

Niobium(III) ChlorideNbCl3199.2654

Niobium(V) Dihydrogen PhosphateNb(H2PO4)5577.84259

Niobium NitrideNbN106.9131

Niobium(III) DichromateNb2(Cr2O7)3833.77676

Niobium HydroxideNb(OH)3143.9284

Niobium(V) PerchlorateNb(ClO4)5590.15938

Niobium(V) HypochloriteNb(ClO)5350.16838

Niobium(III) HypochloriteNb(ClO)3247.26358

Niobium(V) CarbonateNb2(CO3)5485.85726

Niobium(III) TartrateNb2(C4H4O6)3630.02564

Niobium(III) ChromateNb2(CrO4)3533.79386

Niobium(V) HexafluorosilicateNb2(SiF6)5896.192356

7 0
3 years ago
How many grams of LiNO2 are required to make 250 mL of 0.75 Molarity solution?
Katarina [22]

Answer:

159 g OF LiNO2 WILL BE USED TO MAKE 0.25 L OF 0.75 M SOLUTION.

Explanation:

How many grams of LiNO2 are required to make 250 mL of 0.75 M?

First calculate the molarity in mol per dm3

0.75 M of LiNO2 reacts in 250 mL = 250 /1000 L volume

0.75 M = 0.25 L

In 1 L, the molarity of LiNO2 will be:

= (0.75 * 1/ 0.25) M

= 3 mol/dm3 of LiNO2

Next is to calculate the molarity in g/dm3:

Molarity in mol/dm3 = molarity in g/dm3 / RMM.

RMM of LiNO2

(Li = 7 , N =14 , 0 = 16)

RMM = ( 7 + 14 + 16 * 2) = 53 g/mol

Molarity in mol/dm3 =  Molarity in g/dm3 / RMM

Molarity in g/dm3 = Molarity in mol/dm3 * RMM

Molarity in g/dm3 = 3 * 53

Molarity in g/dm3 = 159 g/dm3.

So therefore, to make 250 mL of 0.75 M of LiNO2, we use 159 grams of LiO2.

8 0
3 years ago
Inferring Relationships Most earthquakes take
Whitepunk [10]

Answer:

california

Explanation:

8 0
3 years ago
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