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3 years ago

Explain what the terms "Pyranose" and "Furanose" represent

Chemistry

1 answer:

Illusion [34]3 years ago

5 0

Answer:

hhh

Explanation:

Pyranose is collective term for the saccharides which have chemical structure which includes six-membered ring that consists of one oxygen atom and five carbon atoms.

Furanose is collective term for carbohydrates which have chemical structure which includes five-membered ring system that consists of one oxygen atom and four carbon atoms.

Glucose exists both in pyranose and furanose form. It's structure is shown in image.

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Pb(CH3COO)2 + H2S --> PbS + CH3COOH 1. How many moles are produced of PbS when 5.00 grams of Pb(CH3COO)2 is reacted with H2S?

shutvik [7]

Answer:

1. 0.0154mole of PbS

2. Double displacement reaction

Explanation:

First, let write a balanced equation for the reaction. This is illustrated below:

Pb(CH3COO)2 + H2S —> PbS + 2 CH3COOH

Molar Mass of Pb(CH3COO)2 = 207 + 2(12 + 3 + 12 + 16 +16) = 207 + 2(59) = 207 + 118 = 325g

Mass of Pb(CH3COO)2 = 5g

Number of mole = Mass /Molar Mass

Number of mole of Pb(CH3COO)2 = 5/325 = 0.0154mole

From the equation,

1mole of Pb(CH3COO)2 produced 1mole of PbS.

Therefore, 0.0154mole of Pb(CH3COO)2 will also produce 0.0154mole of PbS

2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products

5 0

3 years ago

3) In 5 electron group molecules, what is the difference between axial and equatorial positions? Which groups are removed as lon

shusha [124]

The axial positions the bond angle is 120 degrees and in equatorial positions the bond angle is 90 degrees.

Functional groups on central atom gets reduce if lone pairs are added.

Explanation:

The number of lone pairs and base pairs of electrons tells the geometry of the molecule.

VSEPR Theory helps to know the lone pairs and bond pair electrons on the centre atom of the molecule.

Example of molecule containing 5 electron pairs can have four bond pairs and 1 lone pair.

eg: Cl $F_{3}$

the repulsion is shown as

lp-lp> lp-bp>bp-bp

These are in equatorial position because of the repulsion of lone pairs.

It can have 2 lone pairs and 3 bond pairs. eg. Xe $F_{2}$

Lone pairs in this is also in equatorial position as

lp-lp> lp-bp> bp-bp

In axial positions the bond angle is 120 degrees

in equatorial positions the bond angle is 90 degrees, due to the repulsion in lone pair of electrons.

If 1 lone pair is there it can be replaced by bonding with hydrogen.

If 2 lone pairs are there then bonding with oxygen is there. The covalent bond is formed.

7 0

3 years ago

What does the coefficients in a balanced chemical equation represent

attashe74 [19]

Answer:

th mol

Explanation:

When you balance an equation, you can refer back to the coefficients when calcuating mol and molar mass from the given information about one reactant to antoher reactant ot product. you use the coeffiecients for mol-mol ratio.

for example. if you are given A +3 B -----> 6C + 5D, and you have 10 mol of A and you have to find how many mols of C with 10 mol of A. then you would ratio it as A: C = 10A: 10C= 10(1): 10(6)= 10:60. so with 10 mol A you can make 60 mol C.

8 0

3 years ago

What is the rate law for step 1 of this reaction? express your answer in standard masteringchemistry notation. for example, if t

eimsori [14]

Hehshdhjd shshhsjawkkskssss

7 0

3 years ago

Read 2 more answers

A 27.5g piece of aluminum sits in a room and cools. It loses 6120.0 J of heat. If the initial

madreJ [45]

Answer:

$T_2= -90.0°C$

Explanation:

Hello!

In this case, according to the given description of how the temperature changes for aluminum in agreement to the loss of heat of 6120.0 J, we can use the following equation:

$Q=mC\Delta T=mC(T_2-T_1)\\\\$

Thus, by knowing Q, m, C and the initial temperature, we are able to obtain:

$T_2=T_1+\frac{Q}{mC}\\\\T_2=157.3\°C+\frac{-6120.0J}{27.5g*0.900 J/g\ºC}\\\\T_2= -90.0°C$

Regards!

5 0

3 years ago