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Mamont248 [21]
3 years ago
6

At 25 oC, the rate constant for the first-order decomposition of a pesticide solution is 6.40 x 10-3 min-1. If the starting conc

entration of pesticide is 0.0314 M, what concentration will remain after 62.0 minutes at 25 oC? 3.12 x 10-2 M 47.4 M 2.11 x 10-2 M 4.67 x 10-2 M 8.72 M
Chemistry
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer:

2.11\ * 10^{-2}  is the correct answer to the given question.

Explanation:

Given k=6.40 x 10-3 min-1.

According to the first order reaction .

The concentration of time can be written as

[\ A\ ]\ = \ [\  A_{0}\ ]  * e \ ^\  {-kt}

Here [\ A\ ]_{0} = Initial concentration.

So  [\ A\ ]_{0}= 0.0314 M

Putting this value into the above equation.

0.0314 \ *\ e^{6.40 x 10^{-3} \ *  \ 62.0  }

=0.211 M

This can be written as

=\ 2.11 *\ 10^{-2}

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