Question

If 10.0 moles of O₂ are reacted with excess NO in the reaction below, and only 4.2 mol of NO₂ were collected, then what is the percent yield for the reaction? 2 NO (g) + O₂ (g) → 2 NO₂ (g)

Answer 1

Answer:

Percent yield = 21%

Explanation:

Find:

Percent yield

Computation:

1 mol O₂ produces 2 mol NO₂

So,

10 mol O₂ produces 20 mol NO₂

Percent yield = [Actual yield / Theoretical yield]100

Percent yield = [4.2 / 20]100

Percent yield = 21%